python避免死锁方法实例分析

当两个或者更多的线程在等待资源的时候就会产生死锁，两个线程相互等待。
在本文实例中 thread1 等待thread2释放block , thread2等待thtead1释放ablock，

避免死锁的原则：

1. 一定要以一个固定的顺序来取得锁，这个列子中，意味着首先要取得alock, 然后再去block

2. 一定要按照与取得锁相反的顺序释放锁，这里，应该先释放block,然后是alock

import threading ,time
a = 5
alock = threading.Lock()
b = 5
block = threading.Lock()
def thread1calc():
  print "thread1 acquiring lock a"
  alock.acquire()
  time.sleep(5)
  print "thread1 acquiring lock b"
  block.acquire()
  a+=5
  b+=5
  print "thread1 releasing both locks"
  block.release()
  alock.release()
def thread2calc():
  print "thread2 acquiring lock b"
  block.acquire()
  time.sleep(5)
  print "thread2 acquiring lock a"
  alock.acquire()
  time.sleep(5)
  a+=10
  b+=10
  print "thread2 releasing both locks"
  block.release()
  alock.release()
t = threading.Thread(target = thread1calc)
t.setDaemon(1)
t.start()
t = threading.Thread(target = thread2calc)
t.setDaemon(2)
t.start()
while 1:
  time.sleep(300)

输出：

thread1 acquiring lock a
thread2 acquiring lock b
thread1 acquiring lock b
thread2 acquiring lock a

希望本文所述对大家的Python程序设计有所帮助。