Python获取央视节目单的实现代码

#! /usr/bin/python 
# -*- coding: utf-8 -*- 
import urllib,re,unicodedata,string,sys 
from time import strftime,localtime 
channel={"1":"CCTV-1","2":"CCTV-2","3":"CCTV-3","4":"CCTV-4亚洲", 
  "5":"CCTV-4欧洲","6":"CCTV-4美洲","7":"CCTV-5","8":"CCTV-6", 
  "9":"CCTV-7","10":"CCTV-8","11":"CCTV-9","12":"CCTV-10", 
  "13":"CCTV-11","14":"CCTV-12","15":"CCTV新闻","16":"CCTV少儿", 
  "17":"CCTV音乐","18":"CCTV_E","19":"CCTV-F","20":"CCTV-高清"} 
if __name__=="__main__": 
  print "@@" 
  print "@@ 你可以在命令行后输入数字(1-20)来选择频道 " 
  print "@@ 通过在命令行后键入help获取频道列表" 
  print "@@" 
  if len(sys.argv)==1: 
    Select="8" 
  else: 
    if sys.argv[1]=="help": 
      for i in range(len(channel)): 
        print "%3d : %11s" % (i+1, channel["%s" % (i+1)]), 
        if(i%4 == 3): 
          print "" 
      sys.exit(0) 
    if string.atoi(sys.argv[1])>20 or string.atoi(sys.argv[1])<=0: 
      print "Out of Range. Please Select 1-20." 
      sys.exit(0) 
    else: 
      Select=sys.argv[1] 
  print '正在获取节目单，请稍后...' 
  date=strftime('%Y%m%d',localtime()) 
  respOnse= urllib.urlopen("http://tv.cctv.com/soushi/28/0"+Select+"/"+date+".shtml") 
  Result=response.read() 
  #list=re.findall(r"
(.+&＃63;)(.+&＃63;)",list[0],re.S) 
  morning=[] 
  afternoon=[] 
  listnum=0 
  for i in range(len(list2)): 
    i=re.sub('<.+&＃63;>','',list2[i]) 
    if string.atoi(i[:2])>=12: #将上午的节目于下午的节目分开 
      afternoon.append(i) 
    else: 
      morning.append(i) 
  if len(morning)>len(afternoon): 
    listnum=len(morning) 
  else: 
    listnum=len(afternoon) 
  print "-"*80, 
  print " "*13+"上午节目"+" "*26+"下午节目" 
  print " "*14+"========"+" "*26+"========" 
  for i in range(listnum): 
    if(i

希望本文所述对大家的Python程序设计有所帮助。