java函数参数做返回值_Java中能否利用函数参数来返回值

java能不能把参数当做一个返回值返回啊&＃xff1f;

有这样子的一个方法:

public void itemControlUploadCheck(Map> itemControlMap, DataRecordImpl dataRecord,

SmartCabinet cabinet,List clearItemIdList)

throws Exception {

setItemControlFlag(cabinet, itemControlMap);

if (this.isInHiddenBlock()) {

clearItemsValue(cabinet, itemControlMap, dataRecord,clearItemIdList);

然后clearItemsValue()方法如下&＃xff1a;

public void clearItemsValue(SmartCabinet cabinet, Map> itemControlMap,

DataRecordImpl dataRecord&＃xff0c;List clearItemIdList) throws Exception {

List clearItemIdList &＃61; new ArrayList();

if (((AbstractFormItem) cabinet.getForm().findItem(this.itemId)).getBlock() !&＃61; null) {

FormBlock block &＃61; ((AbstractFormItem) cabinet.getForm().findItem(this.itemId)).getBlock();

List clearFlagIsTrueBlockIdList &＃61; (List) itemControlMap.get("clearFlag");

if (!ArrayUtils.contains(UNAVAILABLE_CLEAR_ITEMS_LIST,

cabinet.getForm().findItem(this.itemId).getTypeDescriptor())

&& clearFlagIsTrueBlockIdList.contains(block.getId())) {

if ("SimpleLayoutBlock".equals(block.getTypeDescriptor())) {

this.clear();

clearItemIdList.add(this.itemId);

}

if ("ListTypeLayoutBlock".equals(block.getTypeDescriptor())) {

this.clear();

}

最后我在如下方法调用&＃xff1a;

protected void itemControlForDocumentUpload(SmartCabinet cabinet, Map> itemControlMap,

DataRecordImpl dataRecord, Binder binder) throws Exception {

if (dataRecord !&＃61; null) {

for (Integer itemId : dataRecord.getItemIdList()) {

((AbstractFormItemData) dataRecord.getData(itemId)).itemControlUploadCheck(itemControlMap,

dataRecord, cabinet, clearItemIdList);

//我能不能在这里得到参数“ clearItemIdList ”&＃xff0c;就是得到clearItemIdList这个歌返回值。

谢谢了