jQuery代码仅在Firebug打开时运行

因此&＃xff0c;您可能想知道为什么只有在浏览器中打开Firebug时才运行jQuery代码。 嗯&＃xff0c;这可能是因为您在代码中使用了console.log命令&＃xff0c;而jQuery代码失败是因为控制台不存在。

要解决此问题&＃xff0c;请将console.log和firebug命令放在以下代码中&＃xff1a;

if (window.console) {console.log(text);
}

确保未安装Firebug的浏览器不会引发Javascript错误

if (!window.console || !console.firebug)
{var names &＃61; ["log", "debug", "info", "warn", "error", "assert", "dir", "dirxml","group", "groupEnd", "time", "timeEnd", "count", "trace", "profile", "profileEnd"];window.console &＃61; {};for (var i &＃61; 0; i }
[/js]

Turn it into a debug function sir?
[js]
function debug(text) {if ((typeof(Debug) !&＃61;&＃61; &＃39;undefined&＃39;) && Debug.writeln) {Debug.writeln(text);}if (window.console && window.console.log) {window.console.log(text);}if (window.opera) {window.opera.postError(text);}if (window.debugService) {window.debugService.trace(text);}
}

如果控制台可用&＃xff0c;请记录错误

if (typeof(console) !&＃61; &＃39;undefined&＃39; && typeof(console.log) &＃61;&＃61; &＃39;function&＃39;) {// If console available, log the error.console.log(&＃39;Problem hiding the form&＃39;, e);
}

From: https://www.sitepoint.com/jquery-code-runs-firebug-open/