C函数ispunct()的用法及示例代码

C库函数 int ispunct(int c) 检查传递的字符是否是标点符号品格的标点符号是任何图形字符（如isgraph）这是不是字母，数字（isalnum），。

声明

以下是ispunct（）函数的声明。

int ispunct(int c);

参数

• c -- 这是要检查的字符。

返回值

这个函数如果c是一个标点符号一样返回一个非零值（true），否则返回零（false）

例子

下面的例子显示ispunct（）函数的用法。

#include#includeint main(){int var1 ='t';int var2 ='1';int var3 ='/';int var4 =' ';if( ispunct(var1)){
printf("var1 = |%c| is a punctuation character
", var1 );}else{
printf("var1 = |%c| is not a punctuation character
", var1 );}if( ispunct(var2)){
printf("var2 = |%c| is a punctuation character
", var2 );}else{
printf("var2 = |%c| is not a punctuation character
", var2 );}if( ispunct(var3)){
printf("var3 = |%c| is a punctuation character
", var3 );}else{
printf("var3 = |%c| is not a punctuation character
", var3 );}if( ispunct(var4)){
printf("var4 = |%c| is a punctuation character
", var4 );}else{
printf("var4 = |%c| is not a punctuation character
", var4 );}return(0);}

让我们编译和运行上面的程序，这将产生以下结果：

var1 = |t| is not a punctuation character
var2 = |1| is not a punctuation character
var3 = |/| is a punctuation character
var4 = | | is not a punctuation character