在现有正则表达式中支持空格字符-EnablingSpaceCharactersinCurrentRegularExpressions

Perhaps the white space you try to match is not in the ascii range. (for example the non-breakable space). So you can try to add the u modifier to extend the \s character class to all the unicode whitespaces (by default \s contains only ascii whitespaces).

您尝试匹配的空白区域可能不在ascii范围内。 (例如不易碎的空间)。因此,您可以尝试添加u修饰符以将\ s字符类扩展为所有unicode空格(默认情况下,仅包含ascii空格)。

So try this:

试试这个:

preg_match( "/^[A-Za-z0-9?.,-=$@!&%';:)(_\s]+$/u", $value )

or this:

preg_match( "/(*UCP)(*UTF8)^[A-Za-z0-9?.,-=$@!&%';:)(_\s]+$/", $value )

Note: I suggest you to perform clever tests to be sure that whitespaces are really the problem. Note2: this pattern matches exactly the same thing, but it uses character ranges (take a look at the ascii table) and the case insensitive modifier i:

注意:我建议你进行巧妙的测试,以确保空白确实是问题所在。注意2:这个模式完全匹配相同的东西,但它使用字符范围(看一下ascii表)和不区分大小写的修饰符i:

preg_match( "/^[!$-'(),-=?@-Z_\s]+$/ui", $value )

It does match whitespace:

它匹配空格:

preg_match("/^[A-Za-z0-9?.,-=$@!&%';:)(_\s]+$/", '   '); // true
preg_match("/^[A-Za-z0-9?.,-=$@!&%';:)(_\s]+$/", 'a a'); // true
preg_match("/^[A-Za-z0-9?.,-=$@!&%';:)(_\s]+$/", 'aaa'); // true
preg_match("/^[A-Za-z0-9?.,-=$@!&%';:)(_\s]+$/", 'a*a'); // false