SyntaxError：codecademy程序中的语法无效-SyntaxError:Invalidsyntaxinacodecademyprogram

This is how the code should be:

这是代码应该是这样的:

pyg = 'ay'

original = raw_input('Enter a word:')

if len(original) > 0 and original.isalpha():
    word = original.lower()
    first = word[0]
    new_word = word + first +pyg
    new_word = new_word[1:]
    print new_word
else:
    print 'empty'

Let's say the input is Hello. This line: new_word = word + first +pyg will give you hellohay but what you need is ellohay so you need to slice the new_wordin order to lose the first h which is new_word[0] so, new_word should start with e, which is new_word[1] this is why you need this line: new_word = new_word[1:]

假设输入为Hello。这一行:new_word = word + first + pyg会给你hellohay但你需要的是ellohay所以你需要切片new_wordin命令以丢失第一个h,即new_word [0]所以,new_word应该以e开头,即new_word [1]这就是你需要这一行的原因:new_word = new_word [1:]

The output is:

输出是:

ellohay

This is wrong: new_word = [1:len(new_word)]

这是错误的:new_word = [1:len(new_word)]

This is right: new_word = new_word[1:len(new_word)]

这是对的:new_word = new_word [1:len(new_word)]

Another thing, if you want to slice starting from i to the end of your list, you can do:

另外,如果你想从i切换到列表的末尾,你可以这样做:

new_word = new_word[1:]

You use square brackets for slicing, but you have to specify the thing you are slicing.

您可以使用方括号进行切片,但必须指定要切片的内容。

Just like you can access specific elements of lists, strings and the like, you can also access sublists and substrings. Like so:

就像您可以访问列表,字符串等特定元素一样,您也可以访问子列表和子字符串。像这样:

a = "this is a long string"
a[0] == "t"
a[0:4] == "this"
a[1:len(a)] == "his is a long string"

You're getting the SyntaxError because you didn't specify the thing you are slicing.

您正在获取SyntaxError,因为您没有指定要切片的内容。

You need to take a slice of new_word, not a slice of nothing.

你需要拿一片new_word,而不是一片什么。