计算数值平方根的方法与实现

# 设置精度为8位有效数字
from decimal import Decimal, getcontext
getcontext().prec = 8

# 定义目标数值
x = 6

# 转换为 Decimal 类型以提高精度
x = Decimal(str(x))
a = x / Decimal('2')
diff = 0

# 使用牛顿迭代法求解平方根
while True:
    b = (a + x / a) / Decimal('2')
    diff = a - b
    a = b
    if abs(diff)         break

print(a)

2.4494898

#include 

int main() {
    // 定义目标数值
    int x = 6;
    
    float a = x / 2.0;
    float diff = 0.0;
    float b = 0.0;
    while (1) {
        b = (a + x / a) / 2.0;
        diff = a - b;
        a = b;
        if (fabs(diff) <0.001) {
            break;
        }
    }
    printf("平方根为%f\n", a);
    return 0;
}

平方根为2.449490