6  

Here's another approach that runs slower (about 1000ms) than the above answer, but has an interesting idea :-)

这是另一种比上述答案慢的方法(大约1000毫秒)，但有一个有趣的想法:-)

Instead of iterating through each property chain, it just picks the last property and uses a look-up-table for the rest to store the intermediate results. This look-up-table will be iterated until there are no property chains left and all values reside on uncocatenated properties.

它没有遍历每个属性链，而是选择最后一个属性，并使用查找表来存储中间结果。这个查找表将被迭代，直到没有剩余的属性链，所有的值都位于未连接的属性上。

JSON.unflatten = function(data) {
    "use strict";
    if (Object(data) !== data || Array.isArray(data))
        return data;
    var regex = /\.?([^.\[\]]+)$|\[(\d+)\]$/,
        props = Object.keys(data),
        result, p;
    while(p = props.shift()) {
        var m = regex.exec(p),
            target;
        if (m.index) {
            var rest = p.slice(0, m.index);
            if (!(rest in data)) {
                data[rest] = m[2] ? [] : {};
                props.push(rest);
            }
            target = data[rest];
        } else {
            target = result || (result = (m[2] ? [] : {}));
        }
        target[m[2] || m[1]] = data[p];
    }
    return result;
};

It currently uses the data input parameter for the table, and puts lots of properties on it - a non-destructive version should be possible as well. Maybe a clever lastIndexOf usage performs better than the regex (depends on the regex engine).

它目前使用表的数据输入参数，并在表上放置了许多属性——一个非破坏性的版本也应该是可能的。也许一个聪明的lastIndexOf usage比regex性能更好(取决于regex引擎)。

See it in action here.

看这里的行动。

4  

3 ½ Years later...

3½年后…

For my own project I wanted to flatten JSON objects in mongoDB dot notation and came up with a simple solution:

对于我自己的项目，我想用mongoDB点表示法简化JSON对象，并提出了一个简单的解决方案:

/**
 * Recursively flattens a JSON object using dot notation.
 *
 * NOTE: input must be an object as described by JSON spec. Arbitrary
 * JS objects (e.g. {a: () => 42}) may result in unexpected output.
 * MOREOVER, it removes keys with empty objects/arrays as value (see
 * examples bellow).
 *
 * @example
 * // returns {a:1, 'b.0.c': 2, 'b.0.d.e': 3, 'b.1': 4}
 * flatten({a: 1, b: [{c: 2, d: {e: 3}}, 4]})
 * // returns {a:1, 'b.0.c': 2, 'b.0.d.e.0': true, 'b.0.d.e.1': false, 'b.0.d.e.2.f': 1}
 * flatten({a: 1, b: [{c: 2, d: {e: [true, false, {f: 1}]}}]})
 * // return {a: 1}
 * flatten({a: 1, b: [], c: {}})
 *
 * @param obj item to be flattened
 * @param {Array.string} [prefix=[]] chain of prefix joined with a dot and prepended to key
 * @param {Object} [current={}] result of flatten during the recursion
 *
 * @see https://docs.mongodb.com/manual/core/document/#dot-notation
 */
function flatten (obj, prefix, current) {
  prefix = prefix || []
  current = current || {}

  // Remember kids, null is also an object!
  if (typeof (obj) === 'object' && obj !== null) {
    Object.keys(obj).forEach(key => {
      this.flatten(obj[key], prefix.concat(key), current)
    })
  } else {
    current[prefix.join('.')] = obj
  }

  return current
}

Features and/or caveats

特性和/或警告

• It only accepts JSON objects. So if you pass something like {a: () => {}} you might not get what you wanted!
• 它只接受JSON对象。因此，如果您传递类似{a:() =>{}的内容，您可能不会得到您想要的!
• It removes empty arrays and objects. So this {a: {}, b: []} is flattened to {}.
• 它删除空数组和对象。所以这个{}，b:[]}被压平为{}。

2  

This code recursively flattens out JSON objects.

这段代码递归地将JSON对象变平。

I included my timing mechanism in the code and it gives me 1ms but I'm not sure if that's the most accurate one.

我在代码中加入了计时机制，它给了我1ms，但我不确定这是否是最准确的。

            var new_json = [{
              "name": "fatima",
              "age": 25,
              "neighbour": {
                "name": "taqi",
                "location": "end of the street",
                "property": {
                  "built in": 1990,
                  "owned": false,
                  "years on market": [1990, 1998, 2002, 2013],
                  "year short listed": [], //means never
                }
              },
              "town": "Mountain View",
              "state": "CA"
            },
            {
              "name": "qianru",
              "age": 20,
              "neighbour": {
                "name": "joe",
                "location": "opposite to the park",
                "property": {
                  "built in": 2011,
                  "owned": true,
                  "years on market": [1996, 2011],
                  "year short listed": [], //means never
                }
              },
              "town": "Pittsburgh",
              "state": "PA"
            }]

            function flatten(json, flattened, str_key) {
                for (var key in json) {
                  if (json.hasOwnProperty(key)) {
                    if (json[key] instanceof Object && json[key] != "") {
                      flatten(json[key], flattened, str_key + "." + key);
                    } else {
                      flattened[str_key + "." + key] = json[key];
                    }
                  }
                }
            }

        var flattened = {};
        console.time('flatten'); 
        flatten(new_json, flattened, "");
        console.timeEnd('flatten');

        for (var key in flattened){
          console.log(key + ": " + flattened[key]);
        }

Output:

输出:

flatten: 1ms
.0.name: fatima
.0.age: 25
.0.neighbour.name: taqi
.0.neighbour.location: end of the street
.0.neighbour.property.built in: 1990
.0.neighbour.property.owned: false
.0.neighbour.property.years on market.0: 1990
.0.neighbour.property.years on market.1: 1998
.0.neighbour.property.years on market.2: 2002
.0.neighbour.property.years on market.3: 2013
.0.neighbour.property.year short listed: 
.0.town: Mountain View
.0.state: CA
.1.name: qianru
.1.age: 20
.1.neighbour.name: joe
.1.neighbour.location: opposite to the park
.1.neighbour.property.built in: 2011
.1.neighbour.property.owned: true
.1.neighbour.property.years on market.0: 1996
.1.neighbour.property.years on market.1: 2011
.1.neighbour.property.year short listed: 
.1.town: Pittsburgh
.1.state: PA

2  

You can use https://github.com/hughsk/flat

您可以使用https://github.com/hughsk/flat

Take a nested Javascript object and flatten it, or unflatten an object with delimited keys.

获取嵌套的Javascript对象并将其展开，或者使用分隔键将对象展开。

var flatten = require('flat')

flatten({
    key1: {
        keyA: 'valueI'
    },
    key2: {
        keyB: 'valueII'
    },
    key3: { a: { b: { c: 2 } } }
})

// {
//   'key1.keyA': 'valueI',
//   'key2.keyB': 'valueII',
//   'key3.a.b.c': 2
// }


var unflatten = require('flat').unflatten

unflatten({
    'three.levels.deep': 42,
    'three.levels': {
        nested: true
    }
})

// {
//     three: {
//         levels: {
//             deep: 42,
//             nested: true
//         }
//     }
// }

2  

ES6 version:

ES6版本:

const flatten = (obj, path = '') => {        
    if (!(obj instanceof Object)) return {[path.replace(/\.$/g, '')]:obj};

    return Object.keys(obj).reduce((output, key) => {
        return obj instanceof Array ? 
             {...output, ...flatten(obj[key], path +  '[' + key + '].')}:
             {...output, ...flatten(obj[key], path + key + '.')};
    }, {});
}

Example:

例子:

console.log(flatten({a:[{b:["c","d"]}]}));
console.log(flatten([1,[2,[3,4],5],6]));

1  

I added +/- 10-15% efficiency to the selected answer by minor code refactoring and moving the recursive function outside of the function namespace.

我通过少量的代码重构和将递归函数移到函数名称空间之外，为所选答案增加了+/- 10-15%的效率。

See my question: Are namespaced functions reevaluated on every call? for why this slows nested functions down.

请参见我的问题:命名空间函数是否在每次调用中都重新计算?这就是为什么这会降低嵌套函数的速度。

function _flatten (target, obj, path) {
  var i, empty;
  if (obj.cOnstructor=== Object) {
    empty = true;
    for (i in obj) {
      empty = false;
      _flatten(target, obj[i], path ? path + '.' + i : i);
    }
    if (empty && path) {
      target[path] = {};
    }
  } 
  else if (obj.cOnstructor=== Array) {
    i = obj.length;
    if (i > 0) {
      while (i--) {
        _flatten(target, obj[i], path + '[' + i + ']');
      }
    } else {
      target[path] = [];
    }
  }
  else {
    target[path] = obj;
  }
}

function flatten (data) {
  var result = {};
  _flatten(result, data, null);
  return result;
}

See benchmark.

看到基准。

1  

Here's mine. It runs in <2ms in Google Apps Script on a sizable object. It uses dashes instead of dots for separators, and it doesn't handle arrays specially like in the asker's question, but this is what I wanted for my use.

这是我的。它在一个相当大的对象上以<2ms的速度运行在谷歌应用程序脚本中。它使用破折号而不是点作为分隔符，它不像asker的问题那样处理数组，但这是我想要的。

function flatten (obj) {
  var newObj = {};
  for (var key in obj) {
    if (typeof obj[key] === 'object' && obj[key] !== null) {
      var temp = flatten(obj[key])
      for (var key2 in temp) {
        newObj[key+"-"+key2] = temp[key2];
      }
    } else {
      newObj[key] = obj[key];
    }
  }
  return newObj;
}

Example:

例子:

var test = {
  a: 1,
  b: 2,
  c: {
    c1: 3.1,
    c2: 3.2
  },
  d: 4,
  e: {
    e1: 5.1,
    e2: 5.2,
    e3: {
      e3a: 5.31,
      e3b: 5.32
    },
    e4: 5.4
  },
  f: 6
}

Logger.log("start");
Logger.log(JSON.stringify(flatten(test),null,2));
Logger.log("done");

Example output:

示例输出:

[17-02-08 13:21:05:245 CST] start
[17-02-08 13:21:05:246 CST] {
  "a": 1,
  "b": 2,
  "c-c1": 3.1,
  "c-c2": 3.2,
  "d": 4,
  "e-e1": 5.1,
  "e-e2": 5.2,
  "e-e3-e3a": 5.31,
  "e-e3-e3b": 5.32,
  "e-e4": 5.4,
  "f": 6
}
[17-02-08 13:21:05:247 CST] done

0  

I'd like to add a new version of flatten case (this is what i needed :)) which, according to my probes with the above jsFiddler, is slightly faster then the currently selected one. Moreover, me personally see this snippet a bit more readable, which is of course important for multi-developer projects.

我想添加一个新版本的flatten case(这是我需要的:))，根据我对上面的jsFiddler的探针，它比当前选择的稍微快一些。此外，我个人认为这段代码可读性更好，这对于多开发项目来说是很重要的。

function flattenObject(graph) {
    let result = {},
        item,
        key;

    function recurr(graph, path) {
        if (Array.isArray(graph)) {
            graph.forEach(function (itm, idx) {
                key = path + '[' + idx + ']';
                if (itm && typeof itm === 'object') {
                    recurr(itm, key);
                } else {
                    result[key] = itm;
                }
            });
        } else {
            Reflect.ownKeys(graph).forEach(function (p) {
                key = path + '.' + p;
                item = graph[p];
                if (item && typeof item === 'object') {
                    recurr(item, key);
                } else {
                    result[key] = item;
                }
            });
        }
    }
    recurr(graph, '');

    return result;
}