如何使用argv使用AWK打印文本文件的第N列-HowtoprinttheNthcolumnofatextfilewithAWKusingargv

Suppose I have a text file with data separated by whitespace into columns. I want to write a shell script which takes as input a filename and a number N and prints out only that column. With awk I can do the following:

假设我有一个文本文件,其中的数据由空格分隔成列。我想编写一个shell脚本,它将文件名和数字N作为输入,只打印出该列。使用awk我可以执行以下操作:

awk  /tmp/out

This code prints out the second column.

此代码打印出第二列。

But how would one wrap that in a shell script so that a arbitrary column could be passed in argv?

但是如何在shell脚本中包装它以便在argv中传递任意列?

2 个解决方案

awk -v x=2 '{print $x}'

#!/bin/sh
num=$1
awk  /tmp/out

awk '{print $'$myvar'}'  /tmp/out