如何让数组在matlab中启动并开始-Howtogetanarraytostartandbeginwhereyouwantinmatlab

4  

This should also work:

这应该也有效：

newArray = oldArray(oldArray>0);

2  

the find command in matlab solves this. try:

matlab中的find命令解决了这个问题。尝试：

if a = [0 0 0 2 3 4 2 0 0 0]; then

如果a = [0 0 0 2 3 4 2 0 0 0];然后

a(find(a==0))=[];

or

要么

a(a==0)=[];

removes the zeros without for loop

删除没有for循环的零

1  

"Logical indexing" is the most efficient way to do something like this.

“逻辑索引”是执行此类操作的最有效方法。

dataWithoutZeros = data(data ~= 0);

This is because in addition to the usual way of indexing matrices in MATLAB, by specifying a set of index positions, you can also specify an array of logical values of the same dimension as the array

这是因为除了在MATLAB中索引矩阵的常用方法之外，通过指定一组索引位置，您还可以指定与数组具有相同维度的逻辑值数组

data = [10 20 30 40];
a = data([1 3]); % a has value [10 30]
b = data(logical([1 0 1 0])); % b has the same value as a

1  

Assuming you only want to cut off the leading and trailing zeroes, you will need a solution that does not get rid of the middle zeroes. In this case I would suggest the following:

假设您只想切断前导零和尾随零，那么您将需要一个不会消除中间零的解决方案。在这种情况下，我会建议如下：

x = [ 0 0 1 2 0 -3 0]
x(find(x,1,'first'):find(x,1,'last'))

Will give:

会给：

1     2     0    -3

If you are worried about precision, try this:

如果你担心精度，试试这个：

x = [ 0 0 1 2 0 -3 0]
idx = abs(x)>1e-12
x(find(idx,1,'first'):find(idx,1,'last'))

0  

Or even, for less effort at the fingertips and arguably less comprehensible, take advantage of a language which thinks that 0 is the same as not true ...

或者甚至，为了减少指尖上的努力并且可以说理解力较低，可以利用一种认为0与真实相同的语言......

myvector(find(myvector))

returns just the non 0 elements of myvector.

只返回myvector的非0元素。