作者：贤慧201077 | 来源：互联网 | 2023-09-18 15:48
const absentStudentsId = [78, 15, 41, 30] // ======> [{stdId: 78, isPresent: false}, {stdId: 15, isPresent: false}, {stdId: 41, isPresent: false}, {stdId: 30, isPresent: false}]
const presentStudentsId = [80, 61] // ======> [{stdId: 80, isPresent: true}, {stdId: 61, isPresent: true}]
const students = [
{ stdId: 78, isPresent: false },
{ stdId: 15, isPresent: false },
{ stdId: 41, isPresent: false },
{ stdId: 30, isPresent: false },
{ stdId: 80, isPresent: true },
{ stdId: 61, isPresent: true },
]
我想实现您在注释行中看到的逻辑。
回答
您可以关闭isPresent并映射新对象。
const
buildObject = isPresent => stdId => ({ stdId, isPresent }),
absentStudentsId = [78, 15, 41, 30],
presentStudentsId = [80, 61],
students = [
...absentStudentsId.map(buildObject(false)),
...presentStudentsId.map(buildObject(true))
];console.log(students);
.as-console-wrapper { max-height: 100% !important; top: 0; }
@SinanYaman correct. [It&＃039;s a curried function](https://stackoverflow.com/questions/32782922/what-do-multiple-arrow-functions-mean-in-Javascript)
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