请教关于使用C#进行微信开发的XML的接收问题

public void getmsg()
        {

            Stream stream = HttpContext.Current.Request.InputStream;
            Byte[] postBytes = new Byte[stream.Length];
            stream.Read(postBytes, 0, (Int32)stream.Length);
            string postString = Encoding.UTF8.GetString(postBytes);
            
            if (!string.IsNullOrEmpty(postString))
            {
                //封装请求类
                
                XmlDocument requestDocXml = new XmlDocument();
                requestDocXml.LoadXml(postString);
                XmlElement rootElement = requestDocXml.DocumentElement;
                textMsg WxXmlModel = new textMsg();
                WxXmlModel.ToUserName = rootElement.SelectSingleNode("ToUserName").InnerText;
                WxXmlModel.FromUserName = rootElement.SelectSingleNode("FromUserName").InnerText;
                WxXmlModel.CreateTime = rootElement.SelectSingleNode("CreateTime").InnerText;
                WxXmlModel.MsgType = rootElement.SelectSingleNode("MsgType").InnerText;
                switch (WxXmlModel.MsgType)
                {
                    case "text"://文本
                        WxXmlModel.Content = rootElement.SelectSingleNode("Content").InnerText;
                        break;
                    
                    default:
                        break;
                }
                requestDocXml.Save("D:/get.xml");
                backmsg(WxXmlModel);//回复消息





                
            }
        }
        public void backmsg(textMsg WxXmlModel)
        {
            

            string textpl = string.Empty;
            textpl = "" +
                      "" +
                     "" +
                     "" + ConvertDateTimeInt(DateTime.Now) + "" +
                      "" +
                      "" +
                      "0" +
                      "";

            XmlDocument xml = new XmlDocument();
            
            xml.LoadXml(textpl);
            

            if (!string.IsNullOrEmpty(textpl))
            {
                HttpContext.Current.Response.Write(xml);
                HttpContext.Current.Response.End();
            }
        }
        public int ConvertDateTimeInt(DateTime dt)
        {
            dt = DateTime.Now;
            string strdt = dt.Year.ToString() + dt.Month.ToString() + dt.Day.ToString() + dt.Hour.ToString() + dt.Minute.ToString();
            strdt = strdt.Substring(2);
            int intdt = Convert.ToInt32(strdt);
            return intdt;
        }

找来找去找不到问题在哪，我直接手动把xml格式的写入读取xml变量，然后保存要发送的xml，出来倒是正常的。请各位指教下问题在哪，不胜感激

9 个解决方案