Swift3：如何将struct转换为Parameters-Swift3:HowtoconvertstructtoParameters

16  

Just implement a dictionaryRepresentation computed variable or function:

只需实现一个dictionaryRepresentation计算变量或函数：

struct UserInfo {
    var userId : Int

    var firstName : String
    var lastName : String

    var dictionaryRepresentation: [String: Any] {
        return [
            "userId" : userId,
            "firstName" : firstName,
            "lastName" : lastName
        ]
    }
}

Usage:

用法：

var user = UserInfo(userId: 1, firstName: "John", lastName: "Skew")
let userDict = user.dictionaryRepresentation

4  

You could use CodableFirebase library. Although it's main purpose is to use it with Firebase Realtime Database and Firestore, it actually does what you need - converts the value into dictionary [String: Any].

您可以使用CodableFirebase库。虽然它的主要用途是将它与Firebase实时数据库和Firestore一起使用，但它实际上可以满足您的需求 - 将值转换为字典[String：Any]。

Your model would look the following:

您的模型将如下所示：

struct UserInfo: Codable {
    var userId : Int
    var firstName : String
    var lastName : String
}

And then you would convert it to dictionary in the following way:

然后您将通过以下方式将其转换为字典：

import CodableFirebase

let model: UserInfo // here you will create an instance of UserInfo
let dict: [String: Any] = try! FirestoreEncoder().encode(model)

3  

You cannot directly pass struct as parameter. You need to convert your struct into [String:Any]. I have added a new variable description that converts your content to dictionary

您不能直接将struct作为参数传递。您需要将结构转换为[String：Any]。我添加了一个新的变量描述，将您的内容转换为字典

struct UserInfo
{
    var userId : Int
    var firstname : String
    var lastname : String


    var description:[String:Any] {
        get {
            return ["userId":userId, "firstname": self.firstname, "lastname": lastname] as [String : Any]
        }
    }
}

And the usage is

用法是

var user = UserInfo(userId: 1, firstname: "John", lastname: "Skew")

// Convert user to Parameters for Alamofire
Alamofire.request("https://httpbin.org/post", parameters: user.description)

2  

If you're going to make parameters to be sent as a POST request then it should take a dictionary format as follows:

如果您要将参数作为POST请求发送，则它应采用字典格式，如下所示：

let userDict = ["userId" : user.userId, "firstname" : user.firstname, "lastname" : user.lastname]

This should work as "parameters" for your networking

这应该作为您的网络的“参数”

2  

In Swift 4 you can use Decodable/Codable Struct

在Swift 4中，您可以使用Decodable / Codable Struct