Django:使用视图和表单复制模型对象-Django:copyamodelobjectusingviewsandforms

I have a Django (1.8) model that has some class based generic views: list, update, delete, detail, create. https://docs.djangoproject.com/en/1.8/ref/class-based-views/

我有一个Django(1.8)模型，它有一些基于类的通用视图:列表、更新、删除、细节、创建。https://docs.djangoproject.com/en/1.8/ref/class-based-views/

On the detail or list view, I have a button that I want to do this:

在detail或list视图中，我有一个按钮，我想这样做:

1. Create a copy of the object
2. 创建对象的副本
3. Load the data into a form and display for the user to edit/save the new object (could use the existing update or create views, or a new one?)
4. 将数据加载到窗体中并显示给用户以编辑/保存新对象(是否可以使用现有的更新或创建视图，或者使用新的视图?)

I can clone the model with this info: How do I clone a Django model instance object and save it to the database?

我可以用以下信息克隆模型:如何克隆一个Django模型实例对象并将其保存到数据库中?

But I can't make the leap to get this done by starting at a view and ending at a form with the copied object data.

但是我不能通过从视图开始，以复制的对象数据结束的形式来实现这一点。

Thanks!

谢谢!

partial views.py

部分views.py

class List(ListView):
  model = Announcement
  template_name = 'announcements/list.html'

class Create(CreateView):
  model = Announcement
  form_class = AnnouncementForm
  template_name = 'announcements/form.html'

  def form_valid(self, form):
    data = form.save(commit=False)
    data.author = self.request.user
    data.save()
    return super(Create, self).form_valid(form)

class Update(UpdateView):
  model = Announcement
  form_class = AnnouncementForm
  template_name = 'announcements/form_update.html'

  @method_decorator(login_required)
  def dispatch(self, *args, **kwargs):
    return super(Update, self).dispatch(*args, **kwargs)

partial forms.py

部分forms.py

class AnnouncementForm(forms.ModelForm):
    class Meta:
        model = Announcement
        exclude = ['author']

partial list.html

部分list.html

{% for object in object_list %}
      
object.title
      Delete
      Edit
      Copy
{% endfor %}

What I hit the "Copy" button in list.html, I want to duplicate the object and open the new duplicate in a form for editing.

我点击列表中的“复制”按钮。html，我想复制这个对象，并在一个窗体中打开新的副本以供编辑。

2 个解决方案

#eg: myapp/5/copy/
#where 5 is the item I want to copy
url(r'^(?P[0-9]+)/copy/$', views.item_copy, name='item_copy'),

def item_copy(request, id):
    new_item = get_object_or_404(MyModel, pk = id)
    new_item.pk = None #autogen a new pk (item_id)
    new_item.name = "Copy of " + new_item.name #need to change uniques

    form =  MyForm(request.POST or None, instance = new_item)

    if form.is_valid():
        form.save()
        return redirect('my_view')

    cOntext= {
        "form": form,
        #other context
    } 

    return render(request, "form.html", context)

class CopyView(ManageAnnouncement, DeleteView):

    def dispatch(self, *args, **kwargs):
        obj = self.get_object()
        obj.pk = None
        copy = obj.save()
        return HttpResponseRedirect('/announcement/edit/%s' %(copy.id))
        # Change the redirect page to the one you need.