调用webapi时，C#不支持授权类型{“error“:“unsupported_grant_type“}

使用postman

使用代码&＃xff0c;代码如下

{ " error ":" unsupported _ grant _ type " }

public static string GetToken(string url,string username ,string password)
{GetTokenDto getTokenDto &＃61; new GetTokenDto() { Username &＃61; username,Password &＃61; password, grant_type &＃61; "password" };//设定小驼峰模式&＃xff0c;属性名首字母小写var setting &＃61; new JsonSerializerSettings{ContractResolver &＃61; new Newtonsoft.Json.Serialization.CamelCasePropertyNamesContractResolver()};string jsonData &＃61; JsonConvert.SerializeObject(getTokenDto, setting);var logger &＃61; SingleService.Services.GetService();ServicePointManager.ServerCertificateValidationCallback &＃61; ServicePointManager.ServerCertificateValidationCallback &＃61; new RemoteCertificateValidationCallback(delegate {return true;});//https请求 忽略证书&＃xff0c;可以直接访问using (HttpClient httpClient &＃61; new HttpClient()){using (HttpRequestMessage request &＃61; new HttpRequestMessage()){using (HttpContent content &＃61; new StringContent(jsonData, Encoding.UTF8, "application/x-www-form-urlencoded"))//using (HttpContent content &＃61; new StringContent(string.Format("grant_type&＃61;password&username&＃61;{0}&password&＃61;{1}",HttpUtility.UrlEncode(username),HttpUtility.UrlEncode(password)), Encoding.UTF8,"application/x-www-form-urlencoded")){string contentType &＃61; content.Headers.ContentType.ToString();request.RequestUri &＃61; new Uri(url);request.Content &＃61; content;request.Method &＃61; new HttpMethod("GET");var result &＃61; httpClient.SendAsync(request).Result;var str &＃61; result.Content.ReadAsStringAsync().Result;logger.Info(typeof(DataSubHelper), str);return str;}}}return url;
}

原因是什么呢&＃xff0c;原因是的默认实现OAuthAuthorizationServerHandler仅接受表单编码(即application/x-www-form-urlencoded)而不是JSON编码(application/JSON).

修改下代码关键部分

using (HttpContent content &＃61; new StringContent(string.Format("grant_type&＃61;password&username&＃61;{0}&password&＃61;{1}",HttpUtility.UrlEncode(username),HttpUtility.UrlEncode(password)), Encoding.UTF8,"application/x-www-form-urlencoded"))

这样就可以返回正确的结果了