作者：再见傻瓜傻瓜_299 | 来源：互联网 | 2023-08-27 19:40
我有以下列表。
keys = ["key1", "key2", "key3"]
value1 = [1,2]
value2 = [10,20]
value3 = [100,200]
我怎样才能得到像[{"key1":1, "key2":10, "key3":100},{"key1":2, "key2":20, "key3":200}]使用 python一样的结果？
我尝试了 for 循环，但找不到任何解决方案。
提前致谢
回答
您可以使用列表理解来首先zip元素化您的值，然后通过根据您的键压缩这些值来创建字典。
>>> [dict(zip(keys, i)) for i in zip(value1, value2, value3)]
[{'key1': 1, 'key2': 10, 'key3': 100}, {'key1': 2, 'key2': 20, 'key3': 200}]
Sure, it gets the job done for the OP for the example posted, but IMHO it&＃039;s too terse an answer for someone ostensibly having trouble with for loops.
@navneethc So I should avoid providing a pythonic answer even though it is concise and correct? If the OP has any questions about this solution they are free to ask follow-up questions. No reason to make assumptions about what other people know, or want to learn about. If they are unfamiliar with list comprehensions, now is great time to learn about them.
That said, what was unreasonable to assume was that I somehow said that you should avoid providing a pythonic answer.
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