作者:程序员那些事 | 来源:互联网 | 2023-02-02 17:16
我正在使用此代码
applicationVariants.all { variant ->
variant.outputs.each { output ->
def SEP = "_"
def flavor = variant.productFlavors[0].name
def buildType =
variant.variantData.variantConfiguration.buildType.name
def version = variant.versionName
def date = new Date()
def formattedDate = date.format('ddMMyy_HHmm')
def newApkName = PROJECT_NAME + SEP + flavor + SEP + buildType + SEP + version + SEP + formattedDate + ".apk"
def file = new File(newApkName)
output.outputFile = file
}
}
当我构建新的apk时更改apk文件的名称,但由于我使用Android Studio 3.0 Canary 2出现此错误:
无法设置只读属性'outputFile'的值....
1> Paweł Nadols..:
正如Android插件3.0迁移指南所示:
用all()
而不是each()
如果您只更改文件名(这是您的情况),请使用outputFileName
而不是output.outputFile
指南中的示例:
// If you use each() to iterate through the variant objects,
// you need to start using all(). That's because each() iterates
// through only the objects that already exist during configuration time—
// but those object don't exist at configuration time with the new model.
// However, all() adapts to the new model by picking up object as they are
// added during execution.
android.applicationVariants.all { variant ->
variant.outputs.all {
outputFileName = "${variant.name}-${variant.versionName}.apk"
}
}
2> Golan Shay..:
见下文:
applicationVariants.all { variant ->
variant.outputs.all { output ->
def newApkName = applicationId + "-" + variant.versionName + "(" + variant.versionCode + ")" + ".apk";
outputFileName = new File("${project.projectDir}/../outputs/apks/" + variant.name, newApkName);
}
}