scrapy怎么在file_path()函数中拿到item？

    def gen_media_requests(self, item, info):

        for image_url in item['cimage_urls']:

            yield scrapy.Request(image_url, meta={'item': item})



    def file_path(self, request, respOnse=None, info=None):

        item = request.meta.get('item', 'test')

        name = item['name']

        image_guid = request.url.split('/')[-1]

        return 'full/%s/%s' % (name, image_guid)