python中list基础与dict拓展

一. list列表扩展的方式有3种

后缀扩展

list.后输入append

2.插入数值

list.insert

3.合并列表

list.extend

 2. 对["cherry", "litchi", "strawberry", "mangosteen", "pomelo", "pineapple", "pitaya", "durian"]进行默认排序

fruit_list &＃61; ["cherry", "litchi", "strawberry", "mangosteen", "pomelo", "pineapple", "pitaya", "durian"]
fruit_list.sort()
print(fruit_list)

 按照第三个字母排序

def sort_func(x):return (x[3])
fruit_list &＃61; ["cherry", "litchi", "strawberry", "mangosteen", "pomelo", "pineapple", "pitaya", "durian"]
fruit_list.sort(key&＃61;sort_func)
print(fruit_list)

三. dict中所有方法的使用 

1.pop移除序列中一个指定元素&＃xff0c;并返回该元素的值

dict_y &＃61; {int: 1, bytes: 2&＃43;2j}
dict_y.pop(int)
print(dict_y)

 2.clear清除全部元素。

dict_y &＃61; {int: 1, bytes: 2&＃43;2j}
dict_y.clear()
print(dict_y)

 3.copy分为深浅靠背

dict_y &＃61; {int: 1, bytes: 2&＃43;2j, float: 1.1}
dict_2y &＃61; dict_y
dict_3y &＃61; dict_y.copy()
dict_y[&＃39;int: 1&＃39;] &＃61; &＃39;int: 3&＃39;
print(dict_y)
print(dict_2y)
print(dict_3y)


dict3为深拷贝不会因为父目录的变化而变化&＃xff0c;dict2为dict1的 引名会随着父目录改变

4.fromkeys&＃xff1a;创造一个新的字典并返回

dict_y &＃61; dict.fromkeys([1, 2, 3], &＃39;hello&＃39;)
print(dict_y)

dict_y &＃61; dict.fromkeys([1, 2, 3], [&＃39;hello&＃39;, &＃39;hi&＃39;])
print(dict_y)

 5.get返回指定的赋值如果没有为缺省值

dict_y &＃61; {int: 1, bytes: 2&＃43;2j }
print(dict_y.get(int))


 6.items以列表形式返回可遍历元素组

dict_y &＃61; {int: 1, bytes: 2&＃43;2j }
print(dict_y.items())

 7.keys返回一个可迭代xulie

dict_y &＃61; {int: 1, bytes: 2&＃43;2j}
print(dict_y.keys())


8. popitem删除元素只留列表最后一个元素

dict_y &＃61; {int: 1, bytes: 2&＃43;2j, float: 1.1}
print(dict_y.popitem())


dict_y &＃61; {int: 1, bytes: 2&＃43;2j}
print(dict_y.popitem())


 9&＃xff0c;setdefault接受一个值或者缺省值并返回该值

dict_y &＃61; {int: 1, bytes: 2&＃43;2j, float: 1.1}
print(dict_y.setdefault(&＃39;com&＃39;, 2&＃43;2j))

10.update使用可使原字典所含元素更新

dict_y &＃61; {int: 1, bytes: 2&＃43;2j, float: 1.1}
dict_2y &＃61; {float: 2.2}
dict_y.update(dict_2y)
print(dict_y)


 11.values返回字典中所包含的值

dict_y &＃61; {int: 1, bytes: 2&＃43;2j, float: 1.1}
print(dict_y.values())