python文件顺序_Python：我如何创建顺序文件名？

I want my program to be able to write files in a sequential format, ie: file1.txt, file2.txt, file3.txt. It is only meant to write a single file upon execution of the code. It can&＃39;t overwrite any existing files, and it MUST be created. I&＃39;m stumped.

解决方案

Two choices:

Counter File.

Check the directory.

Counter File.

with open("thecounter.data","r") as counter:

count&＃61; int( counter.read() )

count &＃43;&＃61; 1

Each time you create a new file, you also rewrite the counter file with the

appropriate number. Very, very fast. However, it&＃39;s theoretically possible to

get the two out of synch. in the event of a crash.

You can also make the counter file slightly smarter by making it a small piece of

Python code.

settings&＃61; {}

execfile( "thecounter.py", settings )

count &＃61; settings[&＃39;count&＃39;]

Then, when you update the file, you write a little piece of Python code: count &＃61; someNumber. You can add comments and other markers to this file to simplify your bookkeeping.

Check the directory.

import os

def numbers( path ):

for filename in os.listdir(path):

name, _ &＃61; os.path.splitext()

yield int(name[4:])

count &＃61; max( numbers( &＃39;/path/to/files&＃39; ) )

count &＃43;&＃61; 1

Slower. Never has a synchronization problem.