python集合输出_python之集合

集合&＃xff1a;可变的数据类型&＃xff0c;他里面的元素是不可变的数据类型&＃xff0c;无序&＃xff0c;不重复

不可变是可哈希

set1 &＃61; set({1,2,3})

set2 &＃61; {1,2,3,[2,3],{‘name‘:‘alex‘}} #集合元素不可变的 所以输出错误

print(set1)

print(set2)

增&＃xff1a;

1.#add

set1.add(‘alex‘)

2.#update

set1.update(‘abc‘) #迭代增加 把a b c分别增加

删&＃xff1a;

1.#pop

set.pop() #随机删除 有返回值

print(set1)

2.#remove

set.remove(‘alex‘) #按元素

3.#clear 清空

set.clear()

4.#del 删除整个集合

查&＃xff1a;(只能for循环查)

for i in set1:

print(i)

交集&＃xff1a;

set1 &＃61; {1,2,3,4,5}

set2 &＃61; {4,5,6,7,8}

set3 &＃61; set1&set2

print(set3)

print(set1.intersection(set2))

并集&＃xff1a;

print(set1 | set2)

print(set2.union())

反交集&＃xff1a;

set1 &＃61; {1,2,3,4,5}

set2 &＃61; {4,5,6,7,8}

print(set1^set2)

print(set1.symmetric_difference(set2))

差集&＃xff1a;

set1 &＃61; {1,2,3,4,5}

set2 &＃61; {4,5,6,7,8}

print(set1-set2)# set1独有的

print(set1.difference())

子集&＃xff1a;

set1 &＃61; {1,2,3,4,5}

set2 &＃61; {4,5,6,7,8}

print(set1

print(set1.issubset())#返回布尔值

超集&＃xff1a;

set1 &＃61; {1,2,3,4,5}

set2 &＃61; {4,5,6,7,8}

print(set1>set2)

print(set1.issuperset())#返回布尔值

print(set1.issubset())#返回布尔值

去重(面试题)&＃xff1a;

li &＃61; [1,2,33,33,2,1,4,5,6,6]

set1 &＃61;set(li)

li &＃61; list(set1)

print(li)

frozenset不可变集合&＃xff0c;让集合变成不可变集合&＃xff1a;

s &＃61; frozenset(‘barry‘)

只读无序&＃xff1a;

for i in s :

print(i)