python从文件中过去信息_如何使用python从文本文件中提取特定信息？[关闭]

我正在学习python中的文件概念 . 在这里&＃xff0c;我想从文本文件中提取一些文本(在 bold format 中) . 但我不知道该怎么做 .

这是我的示例文本文件&＃xff1a;

{"glossary"&＃xff1a;{"title"&＃xff1a;"example glossary"&＃xff0c;"GlossDiv"&＃xff1a;{ "title": "S" &＃xff0c;"GlossList"&＃xff1a;{"GlossEntry"&＃xff1a;{"ID"&＃xff1a;"SGML"&＃xff0c;"SortAs"&＃xff1a;"SGML"&＃xff0c;"GlossTerm"&＃xff1a;"Standard Generalized Markup Language"&＃xff0c;"Acronym"&＃xff1a;"SGML"&＃xff0c;"Abbrev"&＃xff1a;"ISO 8879:1986"&＃xff0c;"GlossDef"&＃xff1a;{ "para": "A meta-markup language, used to create markup languages such as DocBook." &＃xff0c;"GlossSeeAlso"&＃xff1a;["GML"&＃xff0c;"XML" ]}&＃xff0c;"GlossSee"&＃xff1a;"markup"}}}}}

{"glossary"&＃xff1a;{"title"&＃xff1a;"example glossary"&＃xff0c;"GlossDiv"&＃xff1a;{ "title": "a" &＃xff0c;"GlossList"&＃xff1a;{"GlossEntry"&＃xff1a;{"ID"&＃xff1a;"SGML"&＃xff0c;"SortAs"&＃xff1a;"SGML"&＃xff0c;"GlossTerm"&＃xff1a;"Standard Generalized Markup Language"&＃xff0c;"Acronym"&＃xff1a;"SGML"&＃xff0c;"Abbrev"&＃xff1a;"ISO 8879:1986"&＃xff0c;"GlossDef"&＃xff1a;{ "para": "A meta-markup language, used to create markup languages such as DocBook." &＃xff0c;"GlossSeeAlso"&＃xff1a;["GML"&＃xff0c;"XML" ]}&＃xff0c;"GlossSee"&＃xff1a;"markup"}}}}}

{"glossary"&＃xff1a;{"title"&＃xff1a;"example glossary"&＃xff0c;"GlossDiv"&＃xff1a;{ "title": "b" &＃xff0c;"GlossList"&＃xff1a;{"GlossEntry"&＃xff1a;{"ID"&＃xff1a;"SGML"&＃xff0c;"SortAs"&＃xff1a;"SGML"&＃xff0c;"GlossTerm"&＃xff1a;"Standard Generalized Markup Language"&＃xff0c;"Acronym"&＃xff1a;"SGML"&＃xff0c;"Abbrev"&＃xff1a;"ISO 8879:1986"&＃xff0c;"GlossDef"&＃xff1a;{ "para": "A meta-markup language, used to create markup languages such as DocBook." &＃xff0c;"GlossSeeAlso"&＃xff1a;["GML"&＃xff0c;"XML" ]}&＃xff0c;"GlossSee"&＃xff1a;"markup"}}}}}

{"glossary"&＃xff1a;{"title"&＃xff1a;"example glossary"&＃xff0c;"GlossDiv"&＃xff1a;{ "title": "c" &＃xff0c;"GlossList"&＃xff1a;{"GlossEntry"&＃xff1a;{"ID"&＃xff1a;"SGML"&＃xff0c;"SortAs"&＃xff1a;"SGML"&＃xff0c;"GlossTerm"&＃xff1a;"Standard Generalized Markup Language"&＃xff0c;"Acronym"&＃xff1a;"SGML"&＃xff0c;"Abbrev"&＃xff1a;"ISO 8879:1986"&＃xff0c;"GlossDef"&＃xff1a;{ "para": "A meta-markup language, used to create markup languages such as DocBook." &＃xff0c;"GlossSeeAlso"&＃xff1a;["GML"&＃xff0c;"XML" ]}&＃xff0c;"GlossSee"&＃xff1a;"markup"}}}}}

{"glossary"&＃xff1a;{"title"&＃xff1a;"example glossary"&＃xff0c;"GlossDiv"&＃xff1a;{ "title": "f" &＃xff0c;"GlossList"&＃xff1a;{"GlossEntry"&＃xff1a;{"ID"&＃xff1a;"SGML"&＃xff0c;"SortAs"&＃xff1a;"SGML"&＃xff0c;"GlossTerm"&＃xff1a;"Standard Generalized Markup Language"&＃xff0c;"Acronym"&＃xff1a;"SGML"&＃xff0c;"Abbrev"&＃xff1a;"ISO 8879:1986"&＃xff0c;"GlossDef"&＃xff1a;{ "para": "A meta-markup language, used to create markup languages such as DocBook." &＃xff0c;"GlossSeeAlso"&＃xff1a;["GML"&＃xff0c;"XML" ]}&＃xff0c;"GlossSee"&＃xff1a;"markup"}}}}

我需要像这样的输出&＃xff1a;

"title": "S" ; "para": "A meta-markup language, used to create markup languages such as DocBook."

"title": "a" ; "para": "A meta-markup language, used to create markup languages such as DocBook."

....

任何人都可以帮我在python中做到这一点&＃xff1f;