jQuerywebcam/flash：如何检测网络摄像头是否处于活动状态？-jQuerywebcam/flash:Howtodetectifwebcamisactive?

4  

Add the following function to the debug option of the webcam.

将以下功能添加到网络摄像头的调试选项中。

$("#camera").webcam({
    width: 320,
    // other options etc.
    debug: function(type, message) { 
        if (message === "Camera started") { window.webcam.started = true; } 
    }
});

We cannot test for inactivity to be true (i.e. muted === true) but now we can test for webcam.started being true or undefined/false:

我们无法测试不活动是否为真（即静音=== true）但现在我们可以测试webcam.started是true还是undefined / false：

function capture_image(){
    if( !webcam.started ) { alert("hey, camera not started"); }
}

How to capture the event

如何捕捉事件

There is not an event per se, other than the debug event. You could make one...

除了调试事件之外，本身没有事件。你可以做一个......

First do the following:

首先执行以下操作：

$("#camera").webcam({
    width: 320,
    // other options etc.
    debug: function(type, string) { 
        if (string === "Camera started") { 
            window.webcam.started = true; 
            if (window.webcam.onStarted) { window.webcam.onStarted(); } 
        } 
    }
});

Next add a function to our new event webcam.onStarted:

接下来为我们的新活动webcam.onStarted添加一个功能：

window.webcam.OnStarted= function () {
    alert("Whey, the webcam started");
};

0  

You could use the method .getCameraList() to get all cameras available.

您可以使用方法.getCameraList（）来获取所有可用的摄像头。

onLoad The onLoad callback is called as soon as the registration of the interface is done. In the example above, I use the callback to get a list of all cameras available:

onLoad完成接口注册后立即调用onLoad回调。在上面的示例中，我使用回调来获取所有可用摄像头的列表：

onLoad: function() {
    var cams = webcam.getCameraList();
    for(var i in cams) {
        jQuery("#cams").append("
" + cams[i] + "
");
    } 
}

0  

I think you will need to use the ExternalInterface API to tell the Javascript on your page when the privacy setting has been agreed to.

我认为在同意隐私设置时，您需要使用ExternalInterface API来告知您网页上的Javascript。

However I don't know if you will be able to get to the "image information" you want because flash has control of the camera, so the Javascript will only be able to tell flash to "capture" and image through the ExternalInterface, you will probably have to use flash (ActionScript) to send the image data to a webservice before the Javascript on the page can do anything with it.

但是我不知道你是否能够获得你想要的“图像信息”，因为flash可以控制相机，所以Javascript只能通过ExternalInterface告诉flash“捕获”和图像，你可能必须使用flash（ActionScript）将图像数据发送到Web服务，然后页面上的Javascript才能对其执行任何操作。

HTML5 has an that might suffice, instead of the flash implementation.

HTML5有一个，这可能就足够了，而不是flash实现。

0  

Not sure about all these plugins etc. This works for me, though we're still testing:

不确定所有这些插件等。这对我有用，虽然我们仍在测试：

webcamActive = false;
webcamActive = $("#video").attr('src');