热门标签 | HotTags
当前位置:  开发笔记 > 后端 > 正文

使用sqoop将mysql数据导入到hadoop_MySQL

hadoop的安装配置这里就不讲了。Sqoop的安装也很简单。完成sqoop的安装后,可以这样测试是否可以连接到mysql(注意:mysql的jar包要放到SQOOP_HOMElib下):sqooplist-databases--connectjdbc:mysq
hadoop的安装配置这里就不讲了。

Sqoop的安装也很简单。 完成sqoop的安装后,可以这样测试是否可以连接到mysql(注意:mysql的jar包要放到 SQOOP_HOME/lib 下): sqoop list-databases --connect jdbc:mysql://192.168.1.109:3306/ --username root --password 19891231 结果如下 \ 即说明sqoop已经可以正常使用了。 下面,要将mysql中的数据导入到hadoop中。 我准备的是一个300万条数据的身份证数据表: \ 先启动hive(使用命令行:hive 即可启动) 然后使用sqoop导入数据到hive: sqoop import --connect jdbc:mysql://192.168.1.109:3306/hadoop --username root --password 19891231 --table test_sfz --hive-import sqoop 会启动job来完成导入工作。 \ \ 完成导入用了2分20秒,还是不错的。 在hive中可以看到刚刚导入的数据表: \ 我们来一句sql测试一下数据: select * from test_sfz where id <10; \ 可以看到,hive完成这个任务用了将近25秒,确实是挺慢的(在mysql中几乎是不费时间),但是要考虑到hive是创建了job在hadoop中跑,时间当然多。
接下来,我们会对这些数据进行复杂查询的测试: 我机子的配置如下: \ hadoop 是运行在虚拟机上的伪分布式,虚拟机OS是ubuntu12.04 64位,配置如下: \

TEST 1 计算平均年龄

测试数据:300.8 W 1. 计算广东的平均年龄 mysql:select (sum(year(NOW()) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz where address like &#39;广东%&#39;; 用时: 0.877s hive:select (sum(year(&#39;2014-10-01&#39;) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz where address like &#39;广东%&#39;; 用时:25.012s 2. 对每个城市的的平均年龄进行从高到低的排序 mysql:select address, (sum(year(NOW()) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz GROUP BY address order by ageAvge desc; 用时:2.949s hive:select address, (sum(year(&#39;2014-10-01&#39;) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz GROUP BY address order by ageAvge desc; 用时:51.29s 可以看到,在耗时上面,hive的增长速度较mysql慢。

TEST 2

测试数据:1200W mysql 引擎: MyISAM(为了加快查询速度) 导入到hive: \ 1. 计算广东的平均年龄 mysql:select (sum(year(NOW()) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 where address like &#39;广东%&#39;; 用时: 5.642s hive:select (sum(year(&#39;2014-10-01&#39;) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 where address like &#39;广东%&#39;; 用时:168.259s 2. 对每个城市的的平均年龄进行从高到低的排序 mysql:select address, (sum(year(NOW()) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 GROUP BY address order by ageAvge desc; 用时:11.964s hive:select address, (sum(year(&#39;2014-10-01&#39;) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 GROUP BY address order by ageAvge desc; 用时:311.714s

TEST 3

测试数据:2000W mysql 引擎: MyISAM(为了加快查询速度) 导入到hive: \ (这次用的时间很短!可能是因为TEST2中的导入时,我的主机在做其他耗资源的工作..) 1. 计算广东的平均年龄 mysql:select (sum(year(NOW()) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 where address like &#39;广东%&#39;; 用时: 6.605s hive:select (sum(year(&#39;2014-10-01&#39;) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 where address like &#39;广东%&#39;; 用时:188.206s 2. 对每个城市的的平均年龄进行从高到低的排序 mysql:select address, (sum(year(NOW()) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 GROUP BY address order by ageAvge desc; 用时:19.926s hive:select address, (sum(year(&#39;2014-10-01&#39;) - SUBSTRING(borth,1,4))/count(*)) as ageAvge from test_sfz2 GROUP BY address order by ageAvge desc; 用时:411.816s
推荐阅读
author-avatar
罗然8_907
这个家伙很懒,什么也没留下!
PHP1.CN | 中国最专业的PHP中文社区 | DevBox开发工具箱 | json解析格式化 |PHP资讯 | PHP教程 | 数据库技术 | 服务器技术 | 前端开发技术 | PHP框架 | 开发工具 | 在线工具
Copyright © 1998 - 2020 PHP1.CN. All Rights Reserved | 京公网安备 11010802041100号 | 京ICP备19059560号-4 | PHP1.CN 第一PHP社区 版权所有