对于Lua 5.2, lua 5.2是2011年发布的。国内使用5.1的居多。luaL_register 和luaL_openlibs。这些功能大多数都废弃了 luaL_register这个注册c++的库函数，功能被废弃了。新的api luaL_newlib 网上的资料不多。 下面给出一个使用 luaL_newlib的例子来调用c++ 函数 //this is c++ code#include "stdafx.h"#include "math.h" extern "C"{#include "lua.h"#include "lauxlib.h"#include "lualib.h"};//this is callback function for the luastatic int GetSin(lua_State* luaState){float f;f = (float)luaL_checknumber(luaState, 1);// f = (float)lua_tonumber(luaState,1);float v = sinf(f);lua_pushnumber(luaState,v);return 1;} static const luaL_Reg testlib[] ={{"GetSin",GetSin},{NULL,NULL}}; int luaopenGetLib(lua_State* L){luaL_newlib(L,testlib);return 1; //return one value} int main(int argc, _TCHAR* argv[]){lua_State *L = luaL_newstate();luaL_requiref(L,"sinlib",luaopenGetLib,1); int status = luaL_loadfile(L,"cfg.lua"); //load the cfg.lualua_pcall(L, 0, 0, 0); //execute the loaded cfg.lua int top = lua_gettop(L); double x = 10;double y = 20;double z = 0; lua_getglobal(L, "foo"); bool isf = lua_isfunction(L,-1);lua_pushnumber(L, x); lua_pushnumber(L, y); //execute the lua function (pass two parameters, return one resultif (lua_pcall(L, 2, 1, 0) != 0)luaL_error(L, "error running function 'f': %s",lua_tostring(L, -1));if (!lua_isnumber(L, -1))luaL_error(L, "function 'foo' must return a number");z = lua_tonumber(L, -1);lua_pop(L, 1);lua_close(L); return 0;} cfg.lua的代码在这里 function foo(x, y)--return (x^2 * math.sin(y))/(1 - x)--return x + yreturn sinlib.GetSin(x) + yend
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