leetcode解题之58#LengthofLastWordJava版

leetcode解题之58 # Length of Last Word Java版

Given a string s consists of upper/lower-case alphabets and empty space characters &＃39; &＃39;, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s &＃61; "Hello World",
return 5.

public int lengthOfLastWord(String s) {String[] strs &＃61; s.split(" ");if (strs.length &＃61;&＃61; 0)return 0;return strs[strs.length - 1].length();}

public int lengthOfLastWord(String s) {int length &＃61; s.length();if (length &＃61;&＃61; 0)return 0;int count&＃61;0;int i &＃61; length - 1;while(i>&＃61;0&&s.charAt(i)&＃61;&＃61;&＃39; &＃39;)i--;for(;i>&＃61;0;i--){if(s.charAt(i) !&＃61; &＃39; &＃39;)count&＃43;&＃43;;else break;}System.out.println(count);return count;}