jqueryflotchart近点时突出显示点-jqueryflotcharthighlightdotwhennearpoint

I am making a chart using jQuery flot (plot)

我正在使用jQuery flot制作图表（情节）

https://jsfiddle.net/5gtqwkjg/2/

https://jsfiddle.net/5gtqwkjg/2/

var updateLegendTimeout = null;
var latestPosition = null;

function updateLegend() {

    updateLegendTimeout = null;

    var pos = latestPosition;

    var axes = plot.getAxes();
    if (pos.x  axes.xaxis.max || pos.y  axes.yaxis.max) {
        return;
    }

    /*
            var o = plot.pointOffset({ x: pos.x, y: -1.25 });
            var ctx = plot.getCanvas().getContext("2d");

            ctx.beginPath();
            ctx.moveTo(o.left, o.top);
            o.top = 0;
            ctx.lineTo(o.left, o.top);
            ctx.stroke();
            */

    var i, j, dataset = plot.getData();
    var halfDist = (dataset[0].data[1][0] - dataset[0].data[0][0]) / 2;

    for (i = 0; i  pos.x) {
                break;
            }
        }

        // Now Interpolate

        var y,
        p1 = series.data[j - 1],
            p2 = series.data[j];

        if (p1 == null) y = p2[1];
        else if (p2 == null) y = p1[1];
        else y = p1[1];

        legends.eq(i).text(series.label.replace(/=.*/, "= " + y.toFixed(2)));
        //dataset[i].highlightColor = "#abcdef";
        //plot.highlight(dataset[0].series, dataset[0].datapoint);
    }
}

$("#placeholder").bind("plothover", function (event, pos, item) {
    latestPosition = pos;
    if (!updateLegendTimeout) {
        updateLegendTimeout = setTimeout(updateLegend, 50);
    }
});

I want to add in a functionality that when the user moves the mouse along the x-axis the dot will highlight to indicate what point they are hovering nearest to. I already have the legend reflect the values but how would I highlight the dots?

我想添加一个功能，当用户沿着x轴移动鼠标时，点将突出显示，以指示它们最靠近的位置。我已经有传说反映了价值观，但我如何突出点？

EDIT: Very helpful answers guys! Here is the finished result if anyone is interested https://jsfiddle.net/5gtqwkjg/4/

编辑：非常有用的答案家伙！如果有人有兴趣，这是完成的结果https://jsfiddle.net/5gtqwkjg/4/

2 个解决方案

for (i = 0; i 

for (j = 0; j  pos.x) { 
        for(a = 0; a