java–在JUnit测试用例中访问列表

我有这个ParkingLot.java

public class ParkingLot {
private final int size;
private Car[] slots = null;
List list = new ArrayList();
public ParkingLot(int size) {
this.size = size;
this.slots = new Car[size];
}
public List licenseWithAParticularColour(String colour) {
for (int i = 0; i if (slots[i].getColour() == colour) {
System.out.println(slots[i].getLicense());
list.add(slots[i].getLicense());
return list;
}
}
return null;
}


}

我创建了一个ParkingLotTest.java,如下所示

public class ParkingLotTest {
private Car car1;
private Car car2;
private Car car3;
private Ticket ticket1;
private Ticket ticket2;
private Ticket ticket3;
private ParkingLot parkingLot;
private List list = new ArrayList();
@Before
public void intializeTestEnvironment() throws Exception {
this.car1 = new Car("1234", "White");
this.car2 = new Car("4567", "Black");
this.car3 = new Car("0000", "Red");
this.parkingLot = new ParkingLot(2);
this.ticket1 = parkingLot.park(car1);
this.ticket2 = parkingLot.park(car2);
this.ticket3 = parkingLot.park(car3);
this.list = parkingLot.list;
}
@Test
public void shouldGetLicensesWithAParticularColour() throws Exception {
assertEquals(, parkingLot.licenseWithAParticularColour("White"));
}


}

在上面的测试用例中,我想检查List是否填充了正确的许可证.
1.如何在ParkingLotTest.java中创建一个字段,以便第一个类中的List与第二个类文件中的列表相同.

解决方法:

首先,我认为你不需要在ParkingLot上列出所以你的问题实际上没有多大意义:)

其次,只需在每个测试方法中设置预期结果：

public class ParkingLotTest {
//...
@Test
public void shouldGetLicensesWithAParticularColour() throws Exception {
List expected = new ArrayList();
expected.add(...);
assertEquals(expected, parkingLot.licenseWithAParticularColour("White"));
}
}


并且不要忘记测试意外值或特殊情况.例如：

@Test
public void shouldNotGetLicensesWithANullColour() throws Exception {
...
assertEquals(expected, parkingLot.licenseWithAParticularColour(null));
}
@Test
public void shouldNotGetLicensesWithAnUnknownColour() throws Exception {
...
assertEquals(expected, parkingLot.licenseWithAParticularColour("unknown"));
}


一些补充说明：

>我不会使用Car []作为插槽,而是使用List.
>你真的不需要List ParkingLot中的列表(以及licenseWithAParticularColour的当前实现是错误的).
>我会用Enum作为颜色.