Number Transformation Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 76 Accepted Submission(s): 28

Problem Description

Teacher Mai has an integer x.

He does the following operations k times. In the i-th operation, x becomes the least integer no less than x, which is the multiple of i.

He wants to know what is the number x now.

Input

There are multiple test cases, terminated by a line "0 0".

For each test case, the only one line contains two integers x,k(1<=x<=10^10, 1<=k<=10^10).

Output

For each test case, output one line "Case #k: x", where k is the case number counting from 1.

Sample Input

2520 10
2520 20
0 0

Sample Output

Case #1: 2520
Case #2: 2600

Source

2014 Multi-University Training Contest 8 

#include
int main()
{
    __int64 x,k,i,j,t=0;
    while(scanf("%I64d%I64d",&x,&k)>0&&(x||k))
    {
        i=2;
        while(i<=k)
        {
            if(x%i!=0)
            {
                j=x/i+1; if(j<=i){x=j*k;break;}
                x=i*j;
            }
            else
            {
                j=x/i; if(j<=i){x=j*k;break;}
            }
            i++;
        }
        printf("Case #%I64d: %I64d\n",++t,x);
    }
}

hdu4952Number Transformation (找规律),,

hdu4952Number Transformation (找规律)