Firebase根据子值删除节点-Firebaseremovenodebasedonchildvalue

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To delete all references with child having some particular value first you will need to retrieve all keys ('-KVpQFXnzQkzzrowHxGk', '-KVpQFXnzQkzzrowHxGk' in your case) with equalTo query and then delete those references with remove function.

要删除具有某些特定值的子项的所有引用，您需要使用equalTo查询检索所有键（'-KVpQFXnzQkzzrowHxGk'，' - KVpQFXnzQkzzrowHxGk'），然后使用remove函数删除这些引用。

A sample code is here.

这里有一个示例代码。

var ref = firebase.database(); //root reference to your data
ref.orderByChild('user_id').equalTo('-KTruPWrYO9WFj-TF8Ft')
    .once('value').then(function(snapshot) {
        snapshot.forEach(function(childSnapshot) {
        //remove each child
        ref.child(childSnapshot.key).remove();
    });
});