怎么把一个字节里的比特顺序倒转？

思路1&＃xff1a;查表法。查表法速度最快。

unsigned char reverse_byte(unsigned char x)
{static const unsigned char table[] &＃61; {0x00, 0x80, 0x40, 0xc0, 0x20, 0xa0, 0x60, 0xe0,0x10, 0x90, 0x50, 0xd0, 0x30, 0xb0, 0x70, 0xf0,0x08, 0x88, 0x48, 0xc8, 0x28, 0xa8, 0x68, 0xe8,0x18, 0x98, 0x58, 0xd8, 0x38, 0xb8, 0x78, 0xf8,0x04, 0x84, 0x44, 0xc4, 0x24, 0xa4, 0x64, 0xe4,0x14, 0x94, 0x54, 0xd4, 0x34, 0xb4, 0x74, 0xf4,0x0c, 0x8c, 0x4c, 0xcc, 0x2c, 0xac, 0x6c, 0xec,0x1c, 0x9c, 0x5c, 0xdc, 0x3c, 0xbc, 0x7c, 0xfc,0x02, 0x82, 0x42, 0xc2, 0x22, 0xa2, 0x62, 0xe2,0x12, 0x92, 0x52, 0xd2, 0x32, 0xb2, 0x72, 0xf2,0x0a, 0x8a, 0x4a, 0xca, 0x2a, 0xaa, 0x6a, 0xea,0x1a, 0x9a, 0x5a, 0xda, 0x3a, 0xba, 0x7a, 0xfa,0x06, 0x86, 0x46, 0xc6, 0x26, 0xa6, 0x66, 0xe6,0x16, 0x96, 0x56, 0xd6, 0x36, 0xb6, 0x76, 0xf6,0x0e, 0x8e, 0x4e, 0xce, 0x2e, 0xae, 0x6e, 0xee,0x1e, 0x9e, 0x5e, 0xde, 0x3e, 0xbe, 0x7e, 0xfe,0x01, 0x81, 0x41, 0xc1, 0x21, 0xa1, 0x61, 0xe1,0x11, 0x91, 0x51, 0xd1, 0x31, 0xb1, 0x71, 0xf1,0x09, 0x89, 0x49, 0xc9, 0x29, 0xa9, 0x69, 0xe9,0x19, 0x99, 0x59, 0xd9, 0x39, 0xb9, 0x79, 0xf9,0x05, 0x85, 0x45, 0xc5, 0x25, 0xa5, 0x65, 0xe5,0x15, 0x95, 0x55, 0xd5, 0x35, 0xb5, 0x75, 0xf5,0x0d, 0x8d, 0x4d, 0xcd, 0x2d, 0xad, 0x6d, 0xed,0x1d, 0x9d, 0x5d, 0xdd, 0x3d, 0xbd, 0x7d, 0xfd,0x03, 0x83, 0x43, 0xc3, 0x23, 0xa3, 0x63, 0xe3,0x13, 0x93, 0x53, 0xd3, 0x33, 0xb3, 0x73, 0xf3,0x0b, 0x8b, 0x4b, 0xcb, 0x2b, 0xab, 0x6b, 0xeb,0x1b, 0x9b, 0x5b, 0xdb, 0x3b, 0xbb, 0x7b, 0xfb,0x07, 0x87, 0x47, 0xc7, 0x27, 0xa7, 0x67, 0xe7,0x17, 0x97, 0x57, 0xd7, 0x37, 0xb7, 0x77, 0xf7,0x0f, 0x8f, 0x4f, 0xcf, 0x2f, 0xaf, 0x6f, 0xef,0x1f, 0x9f, 0x5f, 0xdf, 0x3f, 0xbf, 0x7f, 0xff,};return table[x];
}

思路2&＃xff1a;依次检查各个bit&＃xff0c;并逆转顺序

unsigned char reverse(unsigned char c) {int shift;unsigned char result &＃61; 0;for (shift &＃61; 0; shift > shift);}return result;
}

思路3&＃xff1a;依次检查各个bit

template
T reverse(T n, size_t b &＃61; sizeof(T) * CHAR_BITS)
{assert(b <&＃61; sizeof(T) * CHAR_BITS);T rv &＃61; 0;for (size_t i &＃61; 0; i >&＃61; 1)rv &＃61; (rv <<1) | (n & 0x01);return rv;
}