在LINQ到XML中没有结果-NoresultsinLINQtoXML

2  

You currently compare the attribute with some_view. You need to compare its value with that string. Do that by casting the attribute to string and using the equality operator:

您当前正在将属性与some_view进行比较。您需要将它的值与该字符串进行比较。通过将属性转换为string并使用等式运算符:

var test = from _view in root.Descendants("view") where 
    ((string)_view.Attribute("name")) == "some_view" select _view;

This ensures that your code doesn't crash with a NullReferenceException if a view node doesn't have the name attribute.

这将确保如果一个视图节点没有name属性，那么代码不会与NullReferenceException崩溃。

4  

I think you were missing the .Value from the attribute:

我认为您忽略了属性的。value:

var test = (from _view in xml.Descendants("view")
            where _view.Attribute("name") != null && _view.Attribute("name").Value == "some_view" 
            select _view).SingleOrDefault();

Does what you want

什么你想要

1  

I think your problem is the call to XAttribute.Equals. XAttribute is a reference type which although it could override the Equals method, would have misleading behaviour if it did so. I expect you will want Attribute("name").Value.Equals("some_view").

我认为你的问题是调用xattribute.com。XAttribute是一种引用类型，虽然它可以覆盖Equals方法，但是如果它这样做的话会有误导性的行为。我希望您希望属性(“name”). value . equals(“some_view”)。

Not guaranteeing that's the only problem however - I'm not in a position to test at the moment.

但是，不能保证这是唯一的问题——我现在没有能力去测试。

0  

use _view.Attribute("name").Value.Equals("some_view") instead.

使用_view.Attribute(“名字”).Value.Equals(“some_view”)。

0  

your code is correct you just have to access attribute value.

您的代码是正确的，您只需访问属性值。

  XElement root = XElement.Load("params.xml");
   var test = from _view in root.Descendants("view") where 
              _view.Attribute("name").value.Equals("some_view") 
              select _view;