用于获取包括连字符在内的各种令牌的正则表达式-Regularexpressionsforgettingallkindsoftokensincludinghyphens

1  

Sounds like this regex will do what you're looking for:

听起来像这个正则表达式会做你想要的:

@"\b\s?([A-Za-z-]+)\s?\b"

Seems a bit too simple for the regex you've been trying though! Is there something more perhaps?

对于你一直尝试的正则表达式来说似乎有点太简单了!还有更多的东西吗?

0  

Perhaps splitting with a pattern like this:

也许用这样的模式分裂:

@"\s+(?:\p{P}(?!\s))?|\b\p{P}+\s*"

0  

Just in case you want a non-regex way to remove punctuation from sentence and still keep the hypen:

万一你想要一个非正则表达式从句子中删除标点符号并仍然保持爆炸:

import string
s = '"Right now!" she shouted, and hands fluttered in the air - amid a few cheers - for about two minutes.'
x = "".join([c for c in s if c =="-" or c not in string.punctuation])

Outputs:

'Right now she shouted and hands fluttered in the air - amid a few cheers - for about two minutes'

Simply use x.split() to get it tokenized to your desired output.

只需使用x.split()将其标记为您想要的输出。