应用程序启动时没有调用PhonegaphandleOpenURL(iOS)

当应用程序在后台打开时获取警报消息.当我启动应用程序时从后台关闭应用程序时,它不会给我提示警报消息.当应用程序首次启动时,handleOpenURL无法在Javascript中调用.以下是代码

didFinishLaunchingWithOptions代码

NSURL* url = [launchOptions objectForKey:UIApplicationLaunchOptionsURLKey];
NSString* invokeString = nil;

 if (url) {
invokeString = [url absoluteString];
NSLog(@"iPaperReeder launchOptiOns= %@", url);
}

self.viewController.invokeString = invokeString;

AppDelgate.m

if (!url) { return NO; }
NSString* jsString = [NSString stringWithFormat:@"window.setTimeout(function(){ handleOpenURL(\"%@\"); }, 1)", url];
[self.viewController.webView stringByEvaluatingJavascriptFromString:jsString];

// all plugins will get the notification, and their handlers will be  called 
[[NSNotificationCenter defaultCenter] postNotification:[NSNotification notificationWithName:CDVPluginHandleOpenURLNotification object:url]];

return YES;

它应该输出到这个Javascript函数:

 function handleOpenURL(url) { 
alert('invoke: ' + url);
}

请帮我.