需要正则表达式来匹配android4.2.1及更高版本-Needregularexpressiontomatchandroid4.2.1andabove

1  

You can get RELEASE version that has 2 or 3 levels: major, minor and build respectively:

您可以获得具有2或3个级别的RELEASE版本:major,minor和build:

String myVersion = android.os.Build.VERSION.RELEASE;

    String osMajor = "0";
    String osMinor = "0";
    String osBuild = "0";

    if(myVersion.matches("[0-9]+.[0-9]+.[0-9]+")){
        osMajor = myVersion.split("\\.")[0];
        osMinor = myVersion.split("\\.")[1];
        osBuild = myVersion.split("\\.")[2];
    }
    else if(myVersion.matches("[0-9]+.[0-9]+")){
        osMajor = myVersion.split("\\.")[0];
        osMinor = myVersion.split("\\.")[1];

    }

0  

You should look at http://developer.android.com/reference/android/os/Build.VERSION_CODES.html

你应该看看http://developer.android.com/reference/android/os/Build.VERSION_CODES.html

android.os.Build.VERSION.RELEASE returns the user-visible version string. E.g., "1.0" or "3.4b5".

android.os.Build.VERSION.RELEASE返回用户可见的版本字符串。例如,“1.0”或“3.4b5”。

0  

This:

String[] duh = version.split(".");

// Convert the three version numbers to 3 ints, and then....

int vers = (int1 * 100) + (int2 * 10) + int3;