查看用户默认登录shell的*nix命令是什么-Whatisthe*nixcommandtoviewauser'sdefaultloginshell

52  

The canonical way to query the /etc/passwd file for this information is with getent. You can parse getent output with standard tools such as cut to extract the user's login shell. For example:

查询这个信息的/etc/passwd文件的标准方法是使用getent。您可以使用标准工具(如cut)解析getent输出，以提取用户的登录shell。例如:

$ getent passwd $LOGNAME | cut -d: -f7
/bin/bash

18  

The command is finger.

该命令的手指。

[ken@hero ~]$ finger ken
Login: ken                      Name: Kenneth Berland
Directory: /home/ken                    Shell: /bin/tcsh
On since Fri Jun 15 16:11 (PDT) on pts/0 from 70.35.47.130
   1 hour 59 minutes idle
On since Fri Jun 15 18:17 (PDT) on pts/2 from 70.35.47.130
New mail received Fri Jun 15 18:16 2012 (PDT)
     Unread since Fri Jun 15 17:05 2012 (PDT)
No Plan.

6  

The login shell is defined in /etc/passwd. So you can do:

登录shell在/etc/passwd中定义所以你能做什么:

grep username /etc/passwd

2  

I think what you are looking for is this:

我认为你在寻找的是:

#!/bin/bash

cat /etc/passwd | grep $1 | cut -d ':' -f 7

EDIT: @jrrs recommended this version as an improvement... I agree...

编辑:@jrrs推荐这个版本作为改进…我同意……

#!/bin/bash

grep "^$1" /etc/passwd | cut -d ':' -f 7

Save that as get-shell somewhere in your path (probably ~/bin) and then call it like:

将其保存为路径中的某个地方(可能是~/bin)，然后这样调用:

get-shell userfoo