使用JSON请求体测试laravel控制器-TestinglaravelcontrollerswithJSONrequestbody

2  

There is a lot easier way of doing this. You can simply set Input::$json property to the object you want to send as post parameter. See Sample code below

有很多更简单的方法。您可以简单地将输入::$json属性设置为您想要作为post参数发送的对象。请参见下面的示例代码

 $data = array(
        'name' => 'sample name',
        'email' => 'abc@yahoo.com',
 );

 Input::$json = (object)$data;

 Request::setMethod('POST');
 $respOnse= Controller::call('client@create');
 $this->assertNotNull($response);
 $this->assertEquals(200, $response->status());

I hope this helps you with your test cases

我希望这对您的测试用例有所帮助

Update : The original article is available here http://forums.laravel.io/viewtopic.php?id=2521

更新:原始文章可以在这里找到http://forums.laravel.io/viewtopic.php?id=2521

7  

This is how I go about doing this in Laravel4

在Laravel4中，我就是这么做的

// Now Up-vote something with id 53
$this->client->request('POST', '/api/1.0/something/53/rating', array('rating' => 1) );

// I hope we always get a 200 OK
$this->assertTrue($this->client->getResponse()->isOk());

// Get the response and decode it
$jsOnResponse= $this->client->getResponse()->getContent();
$respOnseData= json_decode($jsonResponse);

$responseData will be a PHP object equal to the json response and will allow you to then test the response :)

$responseData将是一个PHP对象，与json响应相等，并允许您随后测试响应:)

6  

In Laravel 5, the call() method has changed:

在Laravel 5中，call()方法已经更改:

$this->call(
    'PUT', 
    $url, 
    [], 
    [], 
    [], 
    ['CONTENT_TYPE' => 'application/json'],
    json_encode($data_array)
);

I think that Symphony's request() method is being called: http://symfony.com/doc/current/book/testing.html

我认为Symphony的request()方法被称为:http://symfony.com/doc/current/book/testing.html

5  

Here's what worked for me.

这是对我有用的。

$postData = array('foo' => 'bar');
$postRequest = $this->action('POST', 'MyController@myaction', array(), array(), array(), array(), json_encode($postData));
$this->assertTrue($this->client->getResponse()->isOk());

That seventh argument to $this->action is content. See docs at http://laravel.com/api/source-class-Illuminate.Foundation.Testing.TestCase.html#_action

第7个参数是$this->操作是内容。在http://laravel.com/api/source-class-Illuminate.Foundation.Testing.TestCase.html _action看到文档

1  

A simple solution would be to use CURL - which will then also allow you to capture the 'response' from the server.

一个简单的解决方案是使用CURL——它还允许您从服务器捕获“响应”。

class AccountControllerTest extends PHPUnit_Framework_TestCase
{

 public function testLogin()
 {
    $url = "account/login";

    $post_data = array(
        'email' => 'user@example.com',
        'password' => 'example_password'
    );
    $cOntent= json_encode($post_data);

    $curl = curl_init($url);
    curl_setopt($curl, CURLOPT_HEADER, false);
    curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($curl, CURLOPT_HTTPHEADER, array("Content-type: application/json"));
    curl_setopt($curl, CURLOPT_POST, true);
    curl_setopt($curl, CURLOPT_POSTFIELDS, $content);

    $json_respOnse= curl_exec($curl);

    $status = curl_getinfo($curl, CURLINFO_HTTP_CODE);

    curl_close($curl);

    $respOnse= json_decode($json_response, true);

    // Do some $this->Assert() stuff here on the $status
  }
}

CURL will actually simulate the raw HTTP post with JSON - so you know you are truly testing your functionality;

CURL将使用JSON模拟原始的HTTP post——因此您知道您正在真正地测试您的功能;

0  

As of Laravel 5.1 there is a much easier way to test JSON controllers via PHPunit. Simply pass an array with the data and it'll get encoded automatically.

从Laravel 5.1开始，有一种更简单的方法可以通过PHPunit测试JSON控制器。只要用数据传递一个数组，它就会被自动编码。

public function testBasicExample()
{
    $this->post('/user', ['name' => 'Sally'])
         ->seeJson([
            'created' => true,
         ]);
}

From the docs: http://laravel.com/docs/5.1/testing#testing-json-apis

从文档:http://laravel.com/docs/5.1/testing # testing-json-apis