使用带有Gulp的requirejs优化器节点模块

有gulp-requirejs插件,但它被列入黑名单,并显示以下消息:" 直接使用require.js模块".

文档非常稀疏,我如何最好地将它与Gulp构建任务结合使用？

在文档中有一个例子:

var requirejs = require('requirejs');

var cOnfig= {
    baseUrl: '../appDir/scripts',
    name: 'main',
    out: '../build/main-built.js'
};

requirejs.optimize(config, function (buildResponse) {
    //buildResponse is just a text output of the modules
    //included. Load the built file for the contents.
    //Use config.out to get the optimized file contents.
    var cOntents= fs.readFileSync(config.out, 'utf8');
}, function(err) {
    //optimization err callback
});

但这对我没什么帮助......这是我最好的尝试:

var gulp = require('gulp'),
    r = require('requirejs').optimize;

var config2 = {
    baseUrl: 'src/js',
    name: 'config',
    out: 'dist/js/main-built.js'
};

gulp.task('scripts3', function() {
    gulp.src(['src/js/**/*.js'])
        .pipe(r(config)
   .pipe(gulp.dest(config.out))
});

但requirejs模块不使用流,因此它不起作用.

还有Gulp友好的amd-optimize,但它与r.js不一样.

要在不调用shell的情况下执行此操作,您可以这样做:

var gulp = require('gulp'),
    rjs = require('requirejs'),

    cOnfig= {
        baseUrl: '../appDir/scripts',
        name: 'main',
        out: '../build/main-built.js'
    };

gulp.task('scripts', function(cb){
    rjs.optimize(config, function(buildResponse){
        // console.log('build response', buildResponse);
        cb();
    }, cb);
});

请参阅:https://github.com/phated/requirejs-example-gulpfile/blob/master/gulpfile.js