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父进程,创建2子进程并使用管道发送数据-Parentprocess,create2childprocessandsenddatawithpipes

Ihavetocreate2childprocessandsenddatafromtheparenttothetwo,soIusedthepipe.我必须创建

I have to create 2 child process and send data from the parent to the two, so I used the pipe.

我必须创建2个子进程并将数据从父进程发送到两个,所以我使用了管道。

If I just use 1 child process and 1 pipe, all works perfectly with fdopen, fscanf and fprintf. Also, if I create 2 pipe and send data to a single process, still works perfectly.

如果我只使用1个子进程和1个管道,则所有这些都与fdopen,fscanf和fprintf完美配合。此外,如果我创建2个管道并将数据发送到单个进程,仍然可以正常工作。

But, if I create a second process and try to read from the second pipe, nothing happen.

但是,如果我创建第二个进程并尝试从第二个管道读取,则没有任何反应。

for example:

例如:

int main() {
    pid_t pid1, pid2;

    int a[2];
    pipe(a);


    pid1 = fork();

    if(pid1 == 0) {
        char x,y;
        FILE *stream;
        stream = fdopen(a[0],"r");

        fscanf(stream,"%c",&x);
        printf("%c\n", x);

        close(a[1]);
        close(a[0]);
    } else {
        int b[2];
        pipe(b);
        pid2 = fork();
        FILE *stream1, *stream2;
        close(a[0]);
        close(b[0]);
        stream1 = fdopen(a[1],"w");
        stream2 = fdopen(b[1],"w");

        fprintf(stream1, "yo bella zio\n");
        fprintf(stream2, "como estas\n");

        fflush(stream1);
        fflush(stream2);
        close(a[1]);
        close(b[1]);

        waitpid (pid1, NULL, 0);
        waitpid (pid2, NULL, 0);

        if (pid2 == 0) {     
            FILE *stream;
            close(b[1]);
            close(a[1]);
            close(a[0]);
            stream = fdopen(b[0],"r");

            fscanf(stream,"%c",&x);

            printf("%c\n", x);
        } else {

        }
    }
}

I really tried all combination. Declare all the pipe together, close or not close pipe. everything but nothing.

我真的尝试了所有组合。将所有管道声明在一起,关闭或不关闭管道。一切都没有。

1 个解决方案

#1


1  

This code fixes the problems identified in my comment and some stray issues.

此代码修复了我的评论中发现的问题和一些流浪问题。

#include 
#include 
#include 
#include 
#include 

int main(void)
{
    pid_t pid1, pid2;
    int a[2];
    int b[2];
    pipe(a);

    pid1 = fork();

    if (pid1 <0)
    {
        fprintf(stderr, "failed to fork child 1 (%d: %s)\n", errno, strerror(errno));
        exit(EXIT_FAILURE);
    }
    else if (pid1 == 0)
    {
        close(a[1]);    // Must be closed before the loop
        FILE *stream = fdopen(a[0], "r");
        if (stream == NULL)
        {
            fprintf(stderr, "failed to create stream for reading (%d: %s)\n", errno, strerror(errno));
            exit(EXIT_FAILURE);
        }

        int c;
        while ((c = getc(stream)) != EOF)
            putchar(c);

        //char x;
        //fscanf(stream, "%c", &x);
        //printf("%c\n", x);

        //close(a[0]);  -- Bad idea once you've used fdopen() on the descriptor 
        printf("Child 1 done\n");
        exit(0);
    }
    else
    {
        pipe(b);
        pid2 = fork();
        if (pid2 <0)
        {
            fprintf(stderr, "failed to fork child 2 (%d: %s)\n", errno, strerror(errno));
            exit(EXIT_FAILURE);
        }
        else if (pid2 == 0)
        {
            close(b[1]);
            close(a[1]);
            close(a[0]);
            FILE *stream = fdopen(b[0], "r");
            if (stream == NULL)
            {
                fprintf(stderr, "failed to create stream for reading (%d: %s)\n", errno, strerror(errno));
                exit(EXIT_FAILURE);
            }

            int c;
            while ((c = getc(stream)) != EOF)
                putchar(c);

            //char x;
            //fscanf(stream, "%c", &x);
            //printf("%c\n", x);

            printf("Child 2 done\n");
            exit(0);
        }
    }

    close(a[0]);
    close(b[0]);

    FILE *stream1 = fdopen(a[1], "w");
    if (stream1 == NULL)
    {
        fprintf(stderr, "failed to create stream for writing (%d: %s)\n", errno, strerror(errno));
        exit(EXIT_FAILURE);
    }
    FILE *stream2 = fdopen(b[1], "w");
    if (stream2 == NULL)
    {
        fprintf(stderr, "failed to create stream for writing (%d: %s)\n", errno, strerror(errno));
        exit(EXIT_FAILURE);
    }

    fprintf(stream1, "yo bella zio\n");
    fprintf(stream2, "como estas\n");

    fflush(stream1);    // Not necessary because fclose flushes the stream
    fflush(stream2);    // Not necessary because fclose flushes the stream
    fclose(stream1);    // Necessary because child won't get EOF until this is closed
    fclose(stream2);    // Necessary because child won't get EOF until this is closed
    //close(a[1]);      -- bad idea once you've used fdopen() on the descriptor
    //close(b[1]);      -- bad idea once you've used fdopen() on the descriptor

    waitpid(pid1, NULL, 0);
    waitpid(pid2, NULL, 0);
    printf("All done!\n");
    return 0;
}

Note that I changed the child processes so that (a) they explicitly exit in the code block, and (b) made their body into a loop so that all the data sent is printed. That required me to move the close(a[1]) in the first child; otherwise, the loop doesn't terminate because the o/s sees that child 1 has the descriptor open for writing.

请注意,我更改了子进程,以便(a)它们在代码块中显式退出,并且(b)将它们的主体放入循环中,以便打印所有发送的数据。这要求我在第一个孩子中移动关闭(a [1]);否则,循环不会终止,因为o / s看到子1的描述符打开以进行写入。

When executed on a Mac running macOS 10.13.6 High Sierra (GCC 8.2.0 as the compiler), I get the output:

在运行macOS 10.13.6 High Sierra(作为编译器的GCC 8.2.0)的Mac上执行时,我得到输出:

yo bella zio
Child 1 done
como estas
Child 2 done
All done!

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