作者:想要铭记的总是轻易忘却- | 来源:互联网 | 2023-09-16 10:13
我想从一个对象创建新的 JS 数组。我解释了我的场景如下。
数组 1:
const arr1 = [
{CODE: "PPM", YARN: 1987, EXP: "IUYT", CARD: "MMN"},
{CODE: "SSW", YARN: 4500, EXP: "NBVC", CARD: "MMN"},
{CODE: "YTR", YARN: 0740, EXP: "NBVC", CARD: "MMN"},
{CODE: "NNH", YARN: 1540, EXP: "MHYT", CARD: "MMN"}
]
数组 2:
const arr2 = [
{PRICE: 6354, CODE: "SSW", WARN: "NBVC"},
{PRICE: 8637, CODE: "NNH", WARN: "MHYT"},
]
预期输出:
output = [
{CODE: "SSW", YARN: 4500, EXP: "NBVC", CARD: "MMN"},
{CODE: "NNH", YARN: 1540, EXP: "MHYT", CARD: "MMN"}
]
解释:
我想比较arr1
和arr2
。如果arr1.code
包含arr2.code
它应该在新数组中。这意味着arr1.code[2] = 'SSW'
。SSW
包含在arr2.code[0]
. 然后arr1.code[2]
应该在新数组中。对arr1.code[3] = 'NNH'
. NNH
包含在arr2.code[1]
.
试过的代码:
console.log(arr1.filter(({ CODE: code1 }) => arr2.some(({ CODE: code2 }) => code2 === code1));
当我尝试上面的代码时,我收到一个错误
渲染错误:“类型错误:无法读取未定义的属性‘价格’”
帮我解决这个问题。
回答
const arr1 = [
{CODE: "PPM", YARN: 1987, EXP: "IUYT", CARD: "MMN"},
{CODE: "SSW", YARN: 4500, EXP: "NBVC", CARD: "MMN"},
{CODE: "YTR", YARN: 0740, EXP: "NBVC", CARD: "MMN"},
{CODE: "NNH", YARN: 1540, EXP: "MHYT", CARD: "MMN"}
]
const arr2 = [
{PRICE: 6354, CODE: "SSW", WARN: "NBVC"},
{PRICE: 8637, CODE: "NNH", WARN: "MHYT"},
]
console.log(arr1.filter(({
CODE: code1
}) => arr2.some(({
CODE: code2
}) => code2 === code1))**)**;
我猜您可能在console.log语句中遗漏了一个括号)。但是,您还没有在代码中使用price关键字。可能是别的什么问题。能分享一下完整的功能吗?