让日期区间更友好&＃xff01;
把常见的日期格式如&＃xff1a;YYYY-MM-DD 转换成一种更易读的格式。
易读格式应该是用月份名称代替月份数字&＃xff0c;用序数词代替数字来表示天 (1st 代替 1).
记住不要显示那些可以被推测出来的信息: 如果一个日期区间里结束日期与开始日期相差小于一年&＃xff0c;则结束日期就不用写年份了。月份开始和结束日期如果在同一个月&＃xff0c;则结束日期月份就不用写了。
另外, 如果开始日期年份是当前年份&＃xff0c;且结束日期与开始日期小于一年&＃xff0c;则开始日期的年份也不用写。
例如:
makeFriendlyDates(["2016-07-01", "2016-07-04"]) 应该返回 ["July 1st, 2016","4th"]
makeFriendlyDates(["2016-07-01", "2018-07-04"]) 应该返回 ["July 1st, 2016", "July 4th, 2018"].
// 简单模拟
function makeFriendlyDates(arr) {
var month &＃61; [
"January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December"
];
var dayth &＃61; ["st", "nd", "rd", "th"];
var ans &＃61; [];
var date1 &＃61; arr[0].split("-");
var date2 &＃61; arr[1].split("-");
var year1 &＃61; (Number(date1[0]) &＃61;&＃61; 2017 && ((new Date(arr[1]) - new Date(arr[0])) / 1000 / 3600 / 24 <365)) ? "" : (", " &＃43; date1[0]);
var month1 &＃61; month[Number(date1[1]) - 1] &＃43; " ";
var day1 &＃61; Number(date1[2]) <&＃61; 3 ? (parseInt(date1[2]) &＃43; dayth[date1[2] - 1]) : (parseInt(date1[2]) &＃43; dayth[3]);
var ans1 &＃61; month1 &＃43; day1 &＃43; year1;
if(new Date(arr[1]).valueOf() &＃61;&＃61; new Date(arr[0]).valueOf() ) {
ans1 &＃61; month1 &＃43; day1 &＃43; ", " &＃43; date1[0]
return [ans1];
}
var year2 &＃61; (((new Date(arr[1]) - new Date(arr[0])) / 1000 / 3600 / 24 <365)) ? "" : (", " &＃43; date2[0]);
var month2 &＃61; ((Number(date1[0]) &＃61;&＃61; Number(date2[0])) && (Number(date1[1]) &＃61;&＃61; Number(date2[1]))) ? "" : month[Number(date2[1]) - 1] &＃43; " ";
var day2 &＃61; Number(date2[2]) <&＃61; 3 ? (parseInt(date2[2]) &＃43; dayth[date2[2] - 1]) : (parseInt(date2[2]) &＃43; dayth[3]);
var ans2 &＃61; month2 &＃43; day2 &＃43; year2;
return [ans1, ans2];
}
makeFriendlyDates(["2018-01-13", "2018-01-13"])
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