作者:手机用户2602917233 | 来源:互联网 | 2023-09-24 13:55
如题:encode32(bin216(Base32.encrypt(1111,ODQ5OTkw)));varBase32newfunction(){varde
如题:
encode32(bin216(Base32.encrypt("1111", "ODQ5OTkw")));
var Base32 = new function() {
var delta = 0x9E3779B8;
function longArrayToString(data, includeLength) {
var length = data.length;
var n = (length - 1) << 2;
if (includeLength) {
var m = data[length - 1];
if ((m < n - 3) || (m > n))
return null;
n = m;
}
for ( var i = 0; i < length; i++) {
data[i] = String.fromCharCode(data[i] & 0xff, data[i] >>> 8 & 0xff, data[i] >>> 16 & 0xff, data[i] >>> 24 & 0xff);
}
if (includeLength) {
return data.join('').substring(0, n);
} else {
return data.join('');
}
}
;
function stringToLongArray(string, includeLength) {
var length = string.length;
var result = [];
for ( var i = 0; i < length; i += 4) {
result[i >> 2] = string.charCodeAt(i) | string.charCodeAt(i + 1) << 8 | string.charCodeAt(i + 2) << 16 | string.charCodeAt(i + 3) << 24;
}
if (includeLength) {
result[result.length] = length;
}
return result;
}
;
this.encrypt = function(string, key) {
if (string == "") {
return "";
}
var v = stringToLongArray(string, true);
var k = stringToLongArray(key, false);
if (k.length < 4) {
k.length = 4;
}
var n = v.length - 1;
var z = v[n], y = v[0];
var mx, e, p, q = Math.floor(6 + 52 / (n + 1)), sum = 0;
while (0 < q--) {
sum = sum + delta & 0xffffffff;
e = sum >>> 2 & 3;
for (p = 0; p < n; p++) {
y = v[p + 1];
mx = (z >>> 5 ^ y << 2) + (y >>> 3 ^ z << 4) ^ (sum ^ y) + (k[p & 3 ^ e] ^ z);
z = v[p] = v[p] + mx & 0xffffffff;
}
y = v[0];
mx = (z >>> 5 ^ y << 2) + (y >>> 3 ^ z << 4) ^ (sum ^ y) + (k[p & 3 ^ e] ^ z);
z = v[n] = v[n] + mx & 0xffffffff;
}
return longArrayToString(v, false);
};
};
function bin216(s) {
var i, l, o = "", n;
s += "";
b = "";
for (i = 0, l = s.length; i < l; i++) {
b = s.charCodeAt(i);
n = b.toString(16);
o += n.length < 2 ? "0" + n : n;
}
return o;
}
var keyStr = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/=";
function encode32(input) {
input = escape(input);
var output = "";
var chr1, chr2, chr3 = "";
var enc1, enc2, enc3, enc4 = "";
var i = 0;
do {
chr1 = input.charCodeAt(i++);
chr2 = input.charCodeAt(i++);
chr3 = input.charCodeAt(i++);
enc1 = chr1 >> 2;
enc2 = ((chr1 & 3) << 4) | (chr2 >> 4);
enc3 = ((chr2 & 15) << 2) | (chr3 >> 6);
enc4 = chr3 & 63;
if (isNaN(chr2)) {
enc3 = enc4 = 64;
} else if (isNaN(chr3)) {
enc4 = 64;
}
output = output + keyStr.charAt(enc1) + keyStr.charAt(enc2) + keyStr.charAt(enc3) + keyStr.charAt(enc4);
chr1 = chr2 = chr3 = "";
enc1 = enc2 = enc3 = enc4 = "";
} while (i < input.length);
return output;
}
加密后key为:ODQ5OTkw value=YTI1NzA0MzA1NmFjYTg1NA==
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求大神贴出java代码!
7 个解决方案
曾经做过一个 js 移植到 java 的项目。工作量还有难度还是不小的
如果可以的话,建议还是 applet 和 js 互调