Pythonregex:替换数字和特殊字符，除非年份。-Pythonregex:replacenumbersandspecialcharactersexceptyears

2  

You could use a simple regex and pass a function to check if it's a year:

您可以使用一个简单的regex并传递一个函数来检查它是否为一年:

import re

def replace_non_year_numbers(m):
  number = int(m.group(0))
  if 1950 <= number <= 2029:
    return str(number)
  else:
    return ''

print(re.sub('\d+', replace_non_year_numbers, 'ab-c 0123 4r. a2017 2010'))
# 'ab-c  r. a2017 2010'

To keep the regex and the logic simple, you could remove special characters in a second step:

为了使regex和逻辑保持简单，您可以在第二步中删除特殊字符:

only_years = re.sub('\d+', replace_non_year_numbers, 'ab-c 0123 4r. a2017 2010')
no_special_char = re.sub('[^A-Za-z0-9 ]', ' ', only_years)
print(re.sub(' +', ' ', no_special_char))
# ab c r a2017 2010

1  

Let's select what you want to keep in your result. Look at the regex:

让我们选择你想要保留的结果。看看正则表达式:

(
  (?

((?

$ cat test.py
import re

pattern = r"(?:(?

$ python test.py
ab c r a 2010 a 1955 abc