Python列表中字符串按相同字母进行嵌套分类并输出

输入&＃xff1a;[‘eat’,‘ate’,‘tea’,‘like’,‘kile’,‘liek’,‘ielk’]
输出&＃xff1a;[[‘eat’,‘ate’,‘tea’],[‘like’,‘kile’,‘liek’,‘ielk’]]

a_list &＃61; [&＃39;eat&＃39;,&＃39;ate&＃39;,&＃39;tea&＃39;,&＃39;like&＃39;,&＃39;kile&＃39;,&＃39;liek&＃39;,&＃39;ielk&＃39;]def list_group(a_list):len_list &＃61; len(a_list)# 结果result &＃61; []# 记录字符串排序后的位置字典dict_location &＃61; {}for value_i in a_list:s &＃61; "".join((lambda x:(x.sort(),x)[1])(list(value_i)))dict_location_keys &＃61; dict_location.keys()if s not in dict_location_keys:dict_location[s] &＃61; len(dict_location_keys)result.append([s])else:result[dict_location[s]].append(value_i) return resultlist_group(a_list)