jqueryajax在没有firebug断点的情况下不工作-jqueryajaxdontworkwithoutfirebugbreakpoint

5  

The reason you have this problem is because you have performed an asynchronous request. This means that the if(rspns == ".") will be reached before the response has been received from the server, and the result will always be false.

您遇到此问题的原因是您已执行异步请求。这意味着在从服务器收到响应之前将到达if(rspns ==“。”),结果将始终为false。

In order to wrap this code in a function the returns a boolean and does not require a callback function (a blocking procedure) you will need to use a synchronous request:

为了在函数中包装此代码,返回一个布尔值,并且不需要回调函数(阻塞过程),您将需要使用同步请求:

function validateEmaiAjax(email) {

  // This is the correct way to initialise a variable with no value in a function
  var val;

  // Make a synchronous HTTP request
  $.ajax({
    url: "https://localhost/Continental%20Tourism/register_ajax.php",
    async: false,
    data: {
      email: email
    },
    success: function(response) {
      // Update the DOM and send response data back to parent function
      $("#warning").html(response);
      val = response;
    }
  });

  // Now this will work
  if(val == ".") {
    return true;
  } else {
    $("#warning").show();
    return false;
  }

}

2  

If you want to make that code work you should use the $.ajax method instead of load and set async to false to make it wait for the response.

如果你想使代码工作,你应该使用$ .ajax方法而不是load并将async设置为false以使其等待响应。

http://api.jquery.com/jQuery.ajax/

$.ajax({
 url:"https://localhost/Continental%20Tourism/register_ajax.php",
 async: false,
 data: {email: email}, 
 success: function(rspns, stat, xml){ 
   val = rspns; 
  }
 });

2  

Why this

else {
    return false;
    $("#warning").show();
}

$("#warning").show(); will never be executed.

$( “#警告”)显示()。将永远不会被执行。

EDIT : There ya go :

编辑:你去:

function validateEmaiAjax(email){
    var URL     = 'https://localhost/Continental%20Tourism/register_ajax.php';
    var Args    = {email: email}

    $('#warning').load(URL, Args, function(html){
        if(html == '.'){
            return true;
        } else {
            $('#warning').show();
            return false;
        }
    });

    return false;
}

Or you can try this also :

或者你也可以尝试这个:

function validateEmaiAjax(email){
    var URL     = 'https://localhost/Continental%20Tourism/register_ajax.php';
    var Args    = {email: email}

    $.ajax({
        url:     URL,
        type:    'GET'
        data:    Args,
        success: function(html){
            if(html == '.'){
                return true;
            } else {
                $('#warning').show();
                return false;
            }
        }
    });

    return false;
}

0  

This is because your function keeps running and hits the if(val == ".") before it's gotten the ajax response back. You need to but that whole if statement inside the ajax callback function.

这是因为你的函数在得到ajax响应之前一直运行并命中if(val ==“。”)。你需要在ajax回调函数中使用整个if语句。

function validateEmaiAjax(email){
    var success;
    $("#warning").load("https://localhost/Continental%20Tourism/register_ajax.php",{email: email}, function(rspns, stat, xml){
        if(rspns == ".")
            success = true;
        else {
            $("#warning").show();
            success = false;
        }
    });
    return success;
}

Also swapped the warning show and return so it would execute

还交换了警告节目并返回以便执行