作者：zj | 来源：互联网 | 2023-08-28 14:18
由于lua5.1不支持位操作，自己写了一个lua的位操作函数，代码如下：方法1：functionXor(num1,num2)localtmp1num1localtmp2num2lo
由于lua5.1不支持位操作，自己写了一个lua的位操作函数，代码如下：
方法1：
function Xor(num1,num2)
local tmp1 = num1
local tmp2 = num2
local str = ""
repeat
local s1 = tmp1 % 2
local s2 = tmp2 % 2
if s1 == s2 then
str = "0"..str
else
str = "1"..str
end
tmp1 = math.modf(tmp1/2)
tmp2 = math.modf(tmp2/2)
until(tmp1 == 0 and tmp2 == 0)
return tonumber(str,2)
end
function And(num1,num2)
local tmp1 = num1
local tmp2 = num2
local str = ""
repeat
local s1 = tmp1 % 2
local s2 = tmp2 % 2
if s1 == s2 then
if s1 == 1 then
str = "1"..str
else
str = "0"..str
end
else
str = "0"..str
end
tmp1 = math.modf(tmp1/2)
tmp2 = math.modf(tmp2/2)
until(tmp1 == 0 and tmp2 == 0)
return tonumber(str,2)
end
function Or(num1,num2)
local tmp1 = num1
local tmp2 = num2
local str = ""
repeat
local s1 = tmp1 % 2
local s2 = tmp2 % 2
if s1 == s2 then
if s1 == 0 then
str = "0"..str
else
str = "1"..str
end
else
str = "1"..str
end
tmp1 = math.modf(tmp1/2)
tmp2 = math.modf(tmp2/2)
until(tmp1 == 0 and tmp2 == 0)
return tonumber(str,2)
end
使用方法如下：
local tmp1 = 0x52
local tmp2 = 0x01
print(Xor(tmp1,tmp2)) --输出tmp1 异或 tmp2 的操作结果
print(And(tmp1,tmp2)) --输出tmp1 与 tmp2 的操作结果
print(Or(tmp1,tmp2)) --输出tmp1 或 tmp2 的操作结果
加入支持负数的位运算操作： 但是负数和负数位操作出来的显示是个整数
如 And(-8,-5) 结果 ：4294967288 在32位机器上就是 -8
function checkNums( nums )
local n = nums
if n >= 0 then
return n
else
n = 0 - n
n = 0xffffffff - n + 1
end
return n
end
function resultCover( n )
local num = n
if num >= 0x80000000 then
num = num - 0xffffffff - 1
end
return num
end
function And(num1,num2)
local tmp1 = checkNums(num1)
local tmp2 = checkNums(num2)
local ret = 0
local count = 0
repeat
local s1 = tmp1 % 2
local s2 = tmp2 % 2
if s1 == s2 and s1 == 1 then
ret = ret + 2^count
end
tmp1 = math.modf(tmp1/2)
tmp2 = math.modf(tmp2/2)
count = count + 1
until(tmp1 == 0 and tmp2 == 0)
return resultCover(ret)
end
function Or(num1,num2)
local tmp1 = checkNums(num1)
local tmp2 = checkNums(num2)
local ret = 0
local count = 0
repeat
local s1 = tmp1 % 2
local s2 = tmp2 % 2
if s1 == s2 and s1 == 0 then
else
ret = ret + 2^count
end
tmp1 = math.modf(tmp1/2)
tmp2 = math.modf(tmp2/2)
count = count + 1
until(tmp1 == 0 and tmp2 == 0)
return resultCover(ret)
end
function Xor(num1,num2)
local tmp1 = checkNums(num1)
local tmp2 = checkNums(num2)
local ret = 0
local count = 0
repeat
local s1 = tmp1 % 2
local s2 = tmp2 % 2
if s1 ~= s2 then
ret = ret + 2^count
end
tmp1 = math.modf(tmp1/2)
tmp2 = math.modf(tmp2/2)
count = count + 1
until(tmp1 == 0 and tmp2 == 0)
return resultCover(ret)
end
5.3开始自带位操作：
& 按位与
| 按位或
~ 按位异或
>> 右移
<< 左移
~ 按位非
使用方法：
c = a & b
c = a | b
c = a ~ b
c = a >> b
c = a << b
c = ~a
https://blog.csdn.net/u013625451/article/details/84644839
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