思考项目求1+2的2次方+3的3次方+4的4次方+5的5次方+6的6次方的值。（异种循环嵌套）

#include 
using namespace std;
int main()
{
    int n = 1, sum = 0, t = 1, j = 1;
    while (n <= 6)
    {
        sum = sum + t;
        n++;
        t = 1;
        do
        {
            t = t * n;
            j++;
        }
        while (j <= n);
        j = 1;
    }
    cout <<"1+2的平方+3的3次方+4的4次方+5的5次方+6的6次方=" <    return 0;
}

#include 
using namespace std;
int main()
{
int sum = 0, n = 1, t=1, j;
do
{
sum = sum + t;
n++;
t = 1;
j=1;
for (j = 1; j <= n; j++)
t = t * n;
}while (n<=6);
cout<<"1+2的平方+3的3次方+4的4次方+5的5次方+6的6次方="<return 0;
}

#include 
using namespace std;
int main()
{
int sum = 0, n , t = 1, j ;
for (n = 1; n <= 6 ; )
{
sum = sum + t;
n++;
t = 1;
j = 1;
while (j <= n)
{
t = t * n;
j++;
}
}
cout<<"1+2的平方+3的3次方+4的4次方+5的5次方+6的6次方="<return 0;
}