作者：为佐殿回来而读书的天使 | 来源：互联网 | 2023-09-06 15:29
Java 中的 Japanese 年表 isLeapYear()方法，示例
原文:https://www . geeksforgeeks . org/Japanese 年表-islapyear-method-in-Java-with-example/
Java . time . chrono . Japanese 年表类的IsLapyear()方法用于区分闰年和非闰年。如果是闰年，它将返回真或假。
语法:
public boolean isLeapYear(long prolepticYear)
参数:该方法以普理年为参数，检查是否为闰年。
返回值:如果前一年是闰年，该方法返回布尔值为真，否则为假。
以下是说明方法的示例:
例 1:
// Java program to demonstrate
// isLeapYear() method
import java.util.*;
import java.io.*;
import java.time.*;
import java.time.chrono.*;
public class GFG {
public static void main(String[] argv)
{
// creating and initializing
// JapaneseDate Object
JapaneseDate hidate
= JapaneseDate.now();
// getting JapaneseChronology
// used in JapaneseDate
JapaneseChronology crono
= hidate.getChronology();
// getting id of this Chronology
// by using isLeapYear() method
boolean flag = crono.isLeapYear(1444);
// display the result
if (flag)
System.out.println(
"this is leap year");
else
System.out.println(
"this is non leap year");
}
}
输出:
例 2:
// Java program to demonstrate
// isLeapYear() method
import java.util.*;
import java.io.*;
import java.time.*;
import java.time.chrono.*;
public class GFG {
public static void main(String[] argv)
{
// creating and initializing
// JapaneseDate Object
JapaneseDate hidate
= JapaneseDate.now();
// getting JapaneseChronology
// used in JapaneseDate
JapaneseChronology crono
= hidate.getChronology();
// getting id of this Chronology
// by using isLeapYear() method
boolean flag = crono.isLeapYear(2005);
// display the result
if (flag)
System.out.println(
"this is leap year");
else
System.out.println(
"this is non leap year");
}
}
输出:
参考:https://docs . Oracle . com/javase/9/docs/API/Java/time/chrono/Japanese seriogram . html # islapyear-long-
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