JS获取指定时间内的所有星期五

项目中有个需求&＃xff0c;根据两个时间获取该时间内所有星期五的那天的日期&＃xff0c;并且生成一个数组&＃xff0c;我先说下我的思路&＃xff0c;

首先获取两个时间内的相差的天数&＃xff0c;然后进行循环&＃xff0c;根据起始日期进行判断是否是周五&＃xff0c;然后获取到下一天的日期在进行判断&＃xff0c;如果是周五的就把他添加到数组&＃xff0c;因为涉及到月份&＃xff0c;闰年二月的问题&＃xff0c;所以有些棘手&＃xff0c;具体解决方法如下代码&＃xff0c;

//获取当前时间是周几function getMyDay(date){var week;if(date.getDay()&＃61;&＃61;0) week&＃61;"周日"if(date.getDay()&＃61;&＃61;1) week&＃61;"周一"if(date.getDay()&＃61;&＃61;2) week&＃61;"周二"if(date.getDay()&＃61;&＃61;3) week&＃61;"周三"if(date.getDay()&＃61;&＃61;4) week&＃61;"周四"if(date.getDay()&＃61;&＃61;5) week&＃61;"周五"if(date.getDay()&＃61;&＃61;6) week&＃61;"周六"return week;}//获取两个时间段相差的天数function daysBetween(DateOne,DateTwo){ var OneMonth &＃61; DateOne.substring(5,DateOne.lastIndexOf (&＃39;-&＃39;)); var OneDay &＃61; DateOne.substring(DateOne.length,DateOne.lastIndexOf (&＃39;-&＃39;)&＃43;1); var OneYear &＃61; DateOne.substring(0,DateOne.indexOf (&＃39;-&＃39;)); var TwoMonth &＃61; DateTwo.substring(5,DateTwo.lastIndexOf (&＃39;-&＃39;)); var TwoDay &＃61; DateTwo.substring(DateTwo.length,DateTwo.lastIndexOf (&＃39;-&＃39;)&＃43;1); var TwoYear &＃61; DateTwo.substring(0,DateTwo.indexOf (&＃39;-&＃39;)); var cha&＃61;((Date.parse(OneMonth&＃43;&＃39;/&＃39;&＃43;OneDay&＃43;&＃39;/&＃39;&＃43;OneYear)- Date.parse(TwoMonth&＃43;&＃39;/&＃39;&＃43;TwoDay&＃43;&＃39;/&＃39;&＃43;TwoYear))/86400000); return Math.abs(cha); }//获取当前日期的下一天日期function GetDateStr(AddDayCount,time) {var dd &＃61; new Date(time);dd.setDate(dd.getDate()&＃43;AddDayCount);//获取AddDayCount天后的日期var y &＃61; dd.getFullYear();var m &＃61; dd.getMonth()&＃43;1;//获取当前月份的日期var d &＃61; dd.getDate();return y&＃43;"-"&＃43;m&＃43;"-"&＃43;d;}var stime &＃61; "2018-01-05"; //起始时间var etime &＃61; "2018-01-24"; //结束时间var d_length &＃61; daysBetween(stime,etime); //获取两个时间段相差的天数var save_stime &＃61; stime; //保存当前时间var all_time &＃61; []; //存放周五的时间数组for (var i &＃61; 0; i